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astraxan [27]
2 years ago
11

Solve the equation6j + 27 = j + 57​

Mathematics
2 answers:
faltersainse [42]2 years ago
7 0

Answer:

6

Step-by-step explanation:

6j + 27 = j + 57

6j - j = 57 - 27

5j = 30

j = 30 / 5

j = 6

kumpel [21]2 years ago
6 0
<h3>Answer:</h3>

6

<h3>Step-by-step explanation:</h3>
  • 6j + 27 = j + 57
  • 6j + 27 - j = 57
  • 6j - j = 57 - 27
  • 5j = 57 - 27
  • 5j = 30
  • j = 30 ÷ 5
  • j = 6
<h3>Conclusion:</h3>

Equation solving 6j + 27 = j + 57 is 6.

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I need all of these awnser a please !
valentinak56 [21]
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180-80-60=40
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X=180-70
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10.180-118=62
So, 180-62-90
=28

11.not confident yet

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3 0
3 years ago
Which values of a and b make the following equation true? a = 11, b = 7 a = 11, b = 10 a = 28, b = 7 a = 28, b = 10
xz_007 [3.2K]

Answer:

The answer is

<h2>a = 11, b = 7</h2>

Step-by-step explanation:

( {5x}^{7}  {y}^{2} )( { - 4x}^{4}  {y}^{5} ) =  - 20 {x}^{a}  {y}^{b}

Multiply the terms on the left side of the equation

That's

- 20 {x}^{11}  {y}^{7}  =  - 20 {x}^{a}  {y}^{b}

Since the bases are the same we can equate the exponents

That's

{x}^{11}  =  {x}^{a}

a = 11

And

{y}^{7}  =  {y}^{b}

b = 11

Therefore

a = 11 and b = 7

Hope this helps you

7 0
3 years ago
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