f(3x - 1) = 6x - 1
Rewrite 6x - 1 as a function of 3x - 1:
6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1
That is,
f(3x - 1) = 2(3x - 1) + 1
which means
f(x) = 2x + 1
and so
f(0) = 2*0 + 1 = 1
Answer:
5
Step-by-step explanation:
hello :
a + b = 9
...(*)
a - b = 6...(**)
add (*) and (**) : 2a =15.....(1)
subsct (**) and (*) : 2b=3 ....(2)
now divid (1) , (2) : 2a/2b = 15/3
means : a/b = 15/3 =5
The values are 5i, -4, 2√2i, -16, -50i and i.
<h3>What is an imaginary number?</h3>
An imaginary number is a number that, when squared, has a negative result, and is defined by its property i² = −1 or i = √-1.
Given are numbers,
1) √-25 = √25*√-1 = 5i
2) √-2√-2 = 2i*2i = 4i² = -4
3) √-8 = √8*√-1 = 2√2i
4) (4i)² = 16*i² = -16
5) (2i)(5i)² = 2i*25i² = 50i³ = -50i
6) i²*i³*
= -1*(-i)*1 = i
Hence, The values are 5i, -4, 2√2i, -16, -50i and i.
For more reference imaginary number, click;
brainly.com/question/6748860
#SPJ1
If we solve this equation:
<span>8.9=logx+7.9
</span>
we get:
<span>logx=<span>1</span></span>
I think is that one that say <-5,-3> yeah because 3×5=15 you have to choose what other number × 3 that equal to that following answer.
