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Anika [276]
3 years ago
14

Solve for x 5x + 6 < 3x + 7

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

5x + 6 < 3x + 7 \\ 5x - 3x < 7 - 6 \\ 2x < 1 \\ x <  \frac{1}{2}

NeTakaya3 years ago
6 0

Answer:

x < 1/2

Step-by-step explanation:

5x + 6 < 3x + 7

2x + 6 < + 7

2x < 1

x < 1/2

You might be interested in
Would appreciate some help
agasfer [191]

Answer:

e) 36x² - 32y³ = (4)(9x² - 8y³)

f) 45a⁴ - 54a³ = (9a³)(5a - 6)

Step-by-step explanation:

e) 36x² - 32y³ = (4)(9x² - 8y³) becuase 4*9 = 36 and 4*8 = 32

f) 45a⁴ - 54a³ = (9a³)(5a - 6) becuase 9*5 = 45 and 9*6 = 54 and when a is multiplied by a³ you get a⁴

(the exponent are added)

PLEASE RATE!! I hope this helps!!
If you have any questions comment below

4 0
2 years ago
Solve for x: 5|2x − 2| + 8 = 18.
Nitella [24]
5|2x-2|+8=18
5|2x+2|=10
|2x+2|=2
by removing the absolute and but + or -
(2x+2) = 2 & (2x+2)=-2
so , x = 0 & x=-2
so it is the second answer
8 0
3 years ago
Will award brainliest to correct answer!
Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

\angle \: ABP =  \frac{180 - 80}{2}  = 50 \degree

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0
2 years ago
selena walks home to school each mm morning and back home each afternoon. altogether she walks 2/3 mile wach day. how far does s
LenaWriter [7]

Answer:



One days trip of to school from home and back home from school is 2/3 of a mile. We want to know how far it is to school from her house.

To solve this, we simply need to take half of the total distance (2/3)

\frac{2}{3} / 2

Next, we need to turn the 2 into a fraction. Every whole number can be made into a fraction by putting it over 1.

\frac{2}{3} / \frac{2}{1}

Because we are dividing, we need to invert the second fraction and then multiply.

\frac{2}{3} * \frac {1}{2}

Next, we multiply the top of the first fraction by the top of the second and the bottom of the first fraction by the bottom of the second.

\frac{2}{6}

Once you reduce, you get:

\frac{1}{3}

4 0
3 years ago
Solve(x+y)^2=(x^2-2xy+y^2) and show your work
Shtirlitz [24]

(x + y)^2 = (x^2 - 2xy + y^2)

First distribute the ^2 on the left side of the equation to each term inside the parenthesis:

x^2+ 2xy + y^2

Now pick one of the variables to solve for and isolate it:

(solving for x)

x^2 + 2xy + y^2 = x^2 - 2xy + y^2

x^2+ 2xy = x^2 - 2xy

2xy = -2xy

-x = x

x = 0

When you solve for y in the equation it will turn out to be 0 as well

7 0
3 years ago
Read 2 more answers
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