Answer:
n has to be at least 16577.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
Out of n randomly selected students she finds that that exactly half attend their home basketball games.
This means that
99% confidence level
So , z is the value of Z that has a pvalue of
, so
.
About how large would n have to be to get a margin of error less than 0.01 for p
We have to find n for which M = 0.01. So
Rounding up
n has to be at least 16577.
