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elena55 [62]
3 years ago
8

Hello again everyone, need help on this Division question pls (:

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0
321.125 is your answer
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Scientific notation of 0.0000000915
saveliy_v [14]

Answer: 9.15 × 10^-8

4 0
3 years ago
Read 2 more answers
Which is the solution to the equation 8.25 + one-fourth w = 10.75? Round to the nearest hundredth if necessary.
bearhunter [10]

Answer:

w=10

Step-by-step explanation:

8.25+1/4w=10.75

8.25+0.25w=10.75

0.25w=10.75-8.25

0.25w=2.5

w=10

I hope this helps

6 0
3 years ago
What is the standard deviation of the data set
Mrac [35]
C. 3.0 is the nearest mean
5 0
3 years ago
- 1/2 (-3/2x + 6x +1) -3
Tcecarenko [31]
-1/2(-3/2x + 6x + 1) - 3

Simplify.

(3/4x - 3x - 1/2) - 3

Get rid of the parenthesis.

3/4x - 3x - 1/2 - 3

Add like terms.

(3/4x - 3x) + (-1/2 - 3)

Simplify.

-2 1/4x + (-3 1/2)

Get rid of the parenthesis.

-2 1/4x - 3 1/2

Hope I helped! :)

4 0
4 years ago
Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h = ?16t + 160t + 12
insens350 [35]

Answer:

The time taken for the flare to hit the ground is approximately 10.7 seconds.

Step-by-step explanation:

Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

To find : How long will it take for the flare to hit the ground?

Solution :

The equation  h =- 16t^2+ 160t + 120 models the h height at t seconds of the flare.

The flare to hit the ground when h=0.

Substitute in the equation,

-16t^2+ 160t + 120=0

Applying quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where, a=-16, b=160 and c=120

x=\frac{-160\pm\sqrt{160^2-4(-16)(120)}}{2(-16)}

x=\frac{-160\pm\sqrt{33280}}{-32}

x=\frac{-160\pm 182.42}{-32}

x=\frac{-160+182.42}{-32},\frac{-160-182.42}{-32}

x=−0.70,10.70

Reject the negative value.

Therefore, the time taken for the flare to hit the ground is approximately 10.7 seconds.

4 0
3 years ago
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