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Marina86 [1]
3 years ago
8

Make A the subject of the formula r=1 А 3

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Step-by-step explanation:

r =  \sqrt{ \frac{А}{3} }

{r}^{2}  =  \frac{А}{3}

А =  3{r}^{2}

HOPE IT HELPS YA

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Give three rational numbers between -2 and -1
Liono4ka [1.6K]

Answer:

-1.9, -1.8, and -1.7 (answers will vary)

Step-by-step explanation:

Since you have to pick a rational number that is between -2 and -1 there is an infinite options you can choose from. A rational number is a number that can be written as a fraction so you could choose a number like -1.0000000000000000000000001 and 1.999999999999999999999999.

7 0
4 years ago
PLZ HELP IM 100% LOST ON THIS
xenn [34]

The equation f(x)=g(x) is

|x-4|-11=-\sqrt{5x}

Some observations:

  • \sqrt{5x} is defined only as long as 5x\ge0, or x\ge0
  • wherever \sqrt{5x} is defined, its value must be non-negative, so that -\sqrt{5x} is never positive
  • by the definition of absolute value, we have |x-4|=x-4 if x\ge4, and |x-4|=-(x-4)=4-x if x. Then

|x-4|-11=\begin{cases}x-15&\text{for }x\ge4\\-x-7&\text{for }x

If x, the equation becomes

-x-7=-\sqrt{5x}\implies x+7=\sqrt{5x}

Taking the square of both sides gives

(x+7)^2=\left(\sqrt{5x}\right)^2\implies x^2+14x+49=5x\implies x^2+9x+49=0

but since the discriminant is 9^2-4\cdot1\cdot49, there are no real solutions.

If x\ge4, then

x-15=-\sqrt{5x}

Taking squares gives

(x-15)^2=\left(-\sqrt{5x}\right)^2\implies x^2-30x+225=5x

and solving by the quadratic formula gives two potential solutions,

x=\dfrac{35\pm5\sqrt{13}}2

which have approximate values of 8.49 and 26.51.

We know for any value of x that g(x)\le0. We have f(8.49)\approx-6.51 and f(26.51)\approx11.51, so only the first solution 8.49 is valid.

8 0
3 years ago
45pts help! what are the solutions of this quadratic equation? -3x^2+1=3x-2
disa [49]

i think B good luck

6 0
3 years ago
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sveta [45]
50 honestly have no clue sorry
8 0
3 years ago
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Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
vladimir1956 [14]

Answer:

its 450 k

Step-by-step explanation:

It is given that the temperature of the gaseous planet is linearly related with height of the atmosphere. we can write this in the mathematical equation:

y = m x +c

where y is the temperature values, x is height, m is the slope and c is the y-intercept. we have been given two sets of value in the image, using which we can find the value of slope in y-intercept.

at x = 18.40 km, y = 147.54 K

⇒147.54 = 18.40 m + c      

⇒c = 147.54 - 18.40 m  ..(1)

at x =78.11 km, y = 567.00 K

⇒567.00 =78.11 m + c       ..(2)

Put equation 1 in 2 and solve:

⇒567.00 =78.11 m + 147.54 - 18.40 m

⇒419.46 = 59.71 m

⇒ m =419.46 ÷59.71 = 7.025 K/km

c = 147.54 - 18.40 × 7.025 = 18.28 K

At height, x = 61.5 km the approximate temperature is :

y = 7.025 K/km ×  61.5 km + 18.28 K = 450.3 K

Thus, the approximate temperature at altitude 61.5 km is 450 K.

7 0
4 years ago
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