The constant of proportionality if y varies inversely as the fourth power of x and when x=3, y=1 is k = 3^¼
<h3>Inverse variation</h3>
y = k ÷ x^¼
where,
- Constant of proportionality = k
When x = 3, y = 1
y = k ÷ x^¼
1 = k ÷ 3^¼
1 = k / 3^¼
1 × 3^¼ = k
k = 3^¼
Therefore, the constant of proportionality if y varies inversely as the fourth power of x and when x=3, y=1 is k = 3¼
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Answer:
t=0
Step-by-step explanation:
First, we expand everything. The left-hand side is -3(2t) - 1(-3), and we expand it to be -6t+3. The right-hand side is t+t+t+3, and we can reduce it to 3t+3. Now that we have both sides of the equation, we set them to each other.
-6t+3=3t+3 (subtract 3 on both sides)
-6t=3t (add 6t to both sides)
9t =0 (divide by 9)
t=0
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Answer:
you have to add them together
No numbers, is the question correct? Are you factoring?