The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
<h3>Vertex Form of a quadratic expression</h3>
Given the quadratic expressions
1.5x^2+6x+......
1.5(x^2 + 4x)
Using the completing the square method
The coefficient of x = 4
Half of the coefficient = 4/2 = 2
The square of the result = 2^2 = 4
The equation is expressed as:
f(x) = 1.5(x^2+4x+ 4) - 4
f(x) = 1.5(x+2)^2 - 4
Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
Learn more on completing the square method here: brainly.com/question/1596209
Answer:
a) x = 128 degrees
b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc. Therefore angle APD = 128 degrees (and not 116 degrees)
Step-by-step explanation:
Given:
attached diagram
ABC is a straight line
Solution:
a) Find x
ABC is a straight line
angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.
x is the central angle of the arc APD
so angle ABD is the inscribed angle which equals half of the arc angle =>
angle ABD = x/2 = 64 degrees
Solve for x
x/2 = 64
x = 2*64
x = 128 degrees
b.
Angle APD is the arc angle, which is equal to the central angle x subtended by the arc. Therefore angle APD = 128 degrees (and not 116 degrees)
200x 9, nine times two hundred,
1) Δ ABC
m∠B + m∠C + m∠BAC = 180⁰
2) m∠DAB + m∠BAC = 180⁰ because m∠DAB and m∠BAC are supplementary angles.
3) m∠B + m∠C + m∠BAC = m∠DAB + m∠BAC
m∠B + m∠C = m∠DAB
32⁰ + x = 98⁰
x=98 - 32 = 66 ⁰
Answer: A. 66⁰.
