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ladessa [460]
4 years ago
9

Daneielle's rectangular bedroom has an area of 12 3/4 square meters.It is 3.4 meters long. How many meters wide is Danielle's be

droom?
Mathematics
1 answer:
harina [27]4 years ago
3 0
12\frac{3}{4} :3.4=12.75:3.4=3.75m
Answer: wide is 3.75 m
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Paul [167]
12 pizzas because

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x/8

X=12.
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3 years ago
Let a = 2i + 3, b= i – 1, and c= -3i + 2. Which expression is equivalent to a -b- c?A. –2i +4B. 4i + 2C. 4i + 4D. -2i + 2
34kurt

Given:

\begin{gathered} a=2i+3 \\ b=i-1 \\ c=-3i+2 \end{gathered}

You know that:

a-b-c=(2i+3)-(i-1)-(-3i+2)

In order to solve the operation, you can follow these steps:

1. Distribute the negative signs. Remember the Sign Rules for Multiplication:

\begin{gathered} +\cdot+=+ \\ -\cdot-=+ \\ +\cdot-=- \\ -\cdot+=- \end{gathered}

Then:

=2i+3-i+1+3i-2

2. Combine the like terms (add the Real Parts and add the Imaginary Parts):

=4i+2

Hence, the answer is: Option B.

3 0
1 year ago
2(8x-11) what is the property
kotegsom [21]

Answer:

Raise 4 4 to the power of 2 2 . Simplify 11+(4)2 11 + ( 4 ) 2 . Raise 4 4 to the power of 2 2 . Add 11 11 and 16 16 .

Step-by-step explanation:

3 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Nancy and Bill collect coins. Nancy has x coins. Bill has 3 coins fewer than two times the number of coins Nancy has. Write and
Hatshy [7]
Nancy & Bill can have 2x-5 coins
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3 years ago
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