All categories

3 years ago

Can you please find the quotient of 9/18÷ 3/6. I am pretty sure that the answer is 1

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

7 0

Answer:

lol yeah its 1, you're right.

Step-by-step explanation:

Vitek1552 [10]3 years ago

6 0

Answer:

It is 1

Step-by-step explanation:

You might be interested in

Pls help with this one no wrong answers pls ;-;

Evgesh-ka [11]

Answer:

Answers below.

Step-by-step explanation:

Inititally as x increases, y remains the same.

Afterword, the slope = 2 for x = 3 to x = 5.

the slope = 1 for x =5 to x =9.

the greatest value of y is y = 4 when x = 5.

4 0

3 years ago

Jonah has a recipe that uses 1 1/2 cups of brown sugar and 2 1/3 cups of flour. Jonah wants to use all of his flour to make as m

S_A_V [24]

Answer:

4 1/2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the prime factorization: 49 i am stuck

ollegr [7]

Answer:

49 can be broken down into 7 * 7 so the prime factorization is simply 7².

8 0

3 years ago

Read 2 more answers

How many tenths are in one whole?how many hundredths?

Nat2105 [25]

10/10 in 1 whole and 1/100 in one whole

4 0

3 years ago

What value of b will cause the system to have an infinite number of solutions?

irga5000 [103]

b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

$\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}$

Let us bring the equations in same form for sake of simplicity in comparison

$\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}$

Now we have two equations

$\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}$

Let us first see what is requirement for system of equations have an infinite number of solutions

If $a_{1} x+b_{1} y+c_{1}=0$ and $a_{2} x+b_{2} y+c_{2}=0$ are two equation

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ then the given system of equation has no infinitely many solutions.

In our case,

$\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}$

As for infinitely many solutions $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}$

Hence b must be equal to -6 for infinitely many solutions for system of equations $y = 6x + b$ and $-3 x+\frac{1}{2} y=-3$

8 0

3 years ago

Can you please find the quotient of 9/18÷ 3/6. I am pretty sure that the answer is 1​

Can you please find the quotient of 9/18÷ 3/6. I am pretty sure that the answer is 1