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olya-2409 [2.1K]
2 years ago
11

If f(x) is a linear function, f( - 1) = 5, and f(2) = 3, find an equation for 8 (2) = f(x) =

Mathematics
1 answer:
Leno4ka [110]2 years ago
3 0
5
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A horse had 4 1/5 scoops of oats in his bucket. He ate 2 1/2 scoops of oats. How much scoops of oats are left in his bucket? Ent
lidiya [134]

Answer:

1 7/10

Step-by-step explanation:

4 1/5-2 1/2 = 17/10 = 1 7/10

8 0
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Please help u don't get it #begging
Jobisdone [24]
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Which segment is a diameter of this circle?<br> Ο TX<br> O VX<br> Ο XY
professor190 [17]

Answer:

The answer is VX.

Step-by-step explanation:

This is because the line segment VX, reaches from one end of the circle to the other, touch both sides of the circle. The other options do not make sense since segment XY does not go through the center of the circle and TX is the radius of the circle. The radius is half the diameter of the circle.

Therefore, the answer is VX.

5 0
2 years ago
The perimeter of a square is 120 inches what is its area
nata0808 [166]

Answer:

A = 900in²

Perimeter   120in

Using the formulas

A = a²

P = 4a

Step-by-step explanation:

Solving for A:

A = 1/16 P² = 1/16 · 120² = 900in²

5 0
2 years ago
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Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
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