Given that the height of the disc is modeled by the function:
h=-16t^2+20t+6
a] The maximum height will be as follows:
At maximum height:
h'(t)=0
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus the maximum height will be:
h(5/8)=-16(5/8)^2+20(5/8)+6
=12.25 ft
b] <span>How long will it take the disc to reach the maximum height?
</span>time taken to reach maximum height will be:
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus time taken to reach maximum height is t=5/8 sec
c]<span>How long does it take for the disc to be caught 3 feet off the ground?
</span>h(t)=-16t^2+20t+6
but
h(t)=3
thus
3=-16t^2+20t+6
solving for t we get:
0=-16t^2+20t+3
factoring the above we get:
t=5/8-/+√37/8
t=-1.5256 or 2.776
since there is no negative time we pick t=2.776
Hence time taken for the disc to be caught 3 ft from the ground is 2.776 ft
Answer:
17.2 in
Step-by-step explanation:
The formula for arc length is s = rФ. Here we are to find r. Solving this formula for r, we get:
r = s/Ф
So, in this problem, r = (9 in) / (π/6) = 54/π in ≈ 17.2 in
Answer:
x=8
Step-by-step explanation:
hope it helps :D
Answer:
8/12 + 3/12
Step-by-step explanation: multiply 2 and 3 by 4 to add these two fractions correctly.
Answer:
B, The answer actually is 2,-7 but i guess they made it backwards But yes, it is B.
Step-by-step explanation:
Hello! Thanks for letting me answer your question! If you have any more questions feel free to ask me! If not, Have a WONDERFUL day and Please don't forget to consider making me Brainliest on your question today!