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2 years ago

Please help me

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

4 0

Answer:

Draw a picture and you'll see a right triangle with sides = 7 and 24 and hypotenuse = r (the cricle's radius). By the Pythagorean Theorem:

r2 = 72 + 242

Area = pi·r2

Step-by-step explanation:

You might be interested in

Represent the geometric series using the explicit formula.

Dennis_Churaev [7]

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Further explanation:

Given sequence is:

3, -6, 12, -24, ...

We have to find the common ratio first.

Common ratio is the ratio between two consecutive terms of a geometric sequence.

It is denoted by r.

So,

$Here,\\a_1=3\\a_2=-6\\a_3=12\\a_4=-24\\r=\frac{a_2}{a_1}=\frac{-6}{3}=-2\\\frac{a_3}{a_2}=\frac{12}{-6}=-2$

General formula for geometric sequence is:

$a_n=a_1r^{n-1}\\Here\\a_n\ is\ the\ nth\ term\\a_1\ is\ the\ first\ term\\and\\r\ is\ common\ ratio$

Putting the values of a1 and r

$a_n=3.(-2)^{n-1}\\f(n)=3.(-2)^{n-1}$

Hence,

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Keywords: Geometric Sequence, Explicit formula

Learn more about geometric sequence at:

#LearnwithBrainly

7 0

3 years ago

A local gym has 2 types of cardio machines, treadmills and elliptical machines. There are 38 cardio machines in all. There are 1

Brilliant_brown [7]

Answer:

14 elliptical machines

Step-by-step explanation:

t = # of treadmills

e = # of elliptical machines

t + e = 38

t = e + 10

Substitute:

e + 10 + e = 38

2e = 28

e = 14

6 0

3 years ago

The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the

Degger [83]

Using the normal distribution, we have that:

The distribution of X is $X \approx (57,22)$ .

The distribution of $\mathbf{\bar{X}}$ is $\bar{X} \approx (57, 5.3358)$ .

0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem, the parameters are given as follows:

$\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358$

Hence:

The distribution of X is $X \approx (57,22)$ .

The distribution of $\mathbf{\bar{X}}$ is $\bar{X} \approx (57, 5.3358)$ .

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{58 - 57}{22}$

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{55 - 57}{22}$

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

$Z = \frac{X - \mu}{s}$

$Z = \frac{58 - 57}{5.3358}$

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

$Z = \frac{X - \mu}{s}$

$Z = \frac{55 - 57}{5.3358}$

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0

1 year ago

I lowkey need help on number five like I don’t get it . Am I doing something wrong cause I feel like I am ? And which equation w

Tpy6a [65]

43,802 round to tha nearest thounsand

5 0

2 years ago

Simplify (-8q^3r^4s^2)^2

koban [17]

Answer:

64q^6r^8s^4

Step-by-step explanation:

(-8q^3r^4s^2)^2

= (-8)^2 q^(3*2) r^(4*2) s^(2*2)

= 64q^6r^8s^4

3 0

3 years ago