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Maru [420]
2 years ago
9

What is the approximate radius of a sphere of volume 528 m³? round the answer to hundreth

Mathematics
2 answers:
makvit [3.9K]2 years ago
5 0

\\ \sf\longmapsto V=\dfrac{4}{3}πr^3

\\ \sf\longmapsto 528=\dfrac{4}{3}πr^3

\\ \sf\longmapsto \pi r^3=528\times \dfrac{3}{4}

\\ \sf\longmapsto πr^3=32(3)

\\ \sf\longmapsto \pi r^3=96

\\ \sf\longmapsto 3.14r^3=96

\\ \sf\longmapsto r^3=\dfrac{96}{3.14}

\\ \sf\longmapsto r^3=30.57

\\ \sf\longmapsto r=3.09m=3.1m

Margarita [4]2 years ago
3 0

\large \boldsymbol {} \sf V_{sp}=\dfrac{4}{3} \pi r^3 \\\\ \displaystyle   \\ \frac{4}{3}  \pi r^3=528 \ m^3 \\\\\\ r=\sqrt[3]{\sf \frac{528}{\pi } \cdot \frac{3}{4} }  \approx5,0\underline 13\approx5,01

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Step-by-step explanation:

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y = 4(1/2)^x.  This is the same as y = ------- or y = -------- * 2^(-x)

                                                             2^x                1

This function is a "decaying exponential."

A suitable table follows:

x      4(2^[-x])         x    y

0      4(2^0)           (0, 4)

1        4(2^1)            (1, 8)

2       4(2^2)           (2, 16)

and so on.

3 0
2 years ago
Make d the subject of h = d/3 + 2
Bumek [7]

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D=3(h-2)

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6 0
3 years ago
Luke is 5 years younger than 3 times Sydney’s age, s . in this situation , what does 3s represent?
Zielflug [23.3K]

Answer:

3.s is 3 times the age of Sydney's which is equals to Luke age + 5            

Step-by-step explanation:

Given Sydney’s age, s

and also Luke is 5 years younger than 3 times Sydney’s age.

Sydney's 3 times age is 3.s

Luke age = Sydney's 3 times age - 5

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8 0
3 years ago
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Step-by-step explanation:

.........................

3 0
2 years ago
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Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm t
Angelina_Jolie [31]
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
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[eqn 1] + [eqn 2] → 3.26 a = 5.5 
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Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
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Now want the resultant force acting on the 20.0 N block: 
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<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
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