Answer:
Step-by-step explanation:
y=4 times 1/2 to the power of x can be written symbolically as
4 4
y = 4(1/2)^x. This is the same as y = ------- or y = -------- * 2^(-x)
2^x 1
This function is a "decaying exponential."
A suitable table follows:
x 4(2^[-x]) x y
0 4(2^0) (0, 4)
1 4(2^1) (1, 8)
2 4(2^2) (2, 16)
and so on.
Answer:
D=3(h-2)
Step-by-step explanation:
h=d/3+2
h-2=d/3+2-2
h-2=d/3
3(h-2)=d/3x3
3(h-2)=d
Answer:
3.s is 3 times the age of Sydney's which is equals to Luke age + 5
Step-by-step explanation:
Given Sydney’s age, s
and also Luke is 5 years younger than 3 times Sydney’s age.
Sydney's 3 times age is 3.s
Luke age = Sydney's 3 times age - 5
Luke age=3.s-5 ⇒ 3.s = Luke age + 5
Hence, 3.s is 3 times the age of Sydney's which is equals to Luke age + 5
Answer:
183$
Step-by-step explanation:
.........................
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>