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2 years ago

Please solve!!!! I have been trying to figure out for the past 20 years of my life>

Mathematics

2 answers:

Kobotan [32]2 years ago

5 0

Answer:

ergerge

Step-by-step explanation:

Rufina [12.5K]2 years ago

5 0

Answer:

What is it freaking asking???

Step-by-step explanation:

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Translate the phrase into a math expression. Twelve more than the quotient of six divided by three. Responses (6÷3)+12 eft paren

aleksandr82 [10.1K]

The given phrase on translation to math expression is (6 ÷ 3) + 12 , the correct option is (a) .

In the question ,

an mathematical phrase is given , that is "Twelve more than the quotient of six divided by three" .

we have to translate it into mathematical expression ,

So , the term quotient of six divided by three is written as 6 ÷ 3 .

and phrase " more " is represented by " + " ,

Hence the given phrase, "Twelve more than the quotient of six divided by three" is (6 ÷ 3) $+$ 12 .

Therefore , The given phrase on translation to math expression is (6 ÷ 3) + 12 , the correct option is (a) .

The given question is incomplete , the complete question is

Translate the phrase into a math expression , "Twelve more than the quotient of six divided by three" .

(a) (6÷3)+12

(b) 6÷(3+12)

(d) 3÷(6+12)

Learn more about Expressions here

brainly.com/question/7360128

#SPJ1

5 0

1 year ago

Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour, start at the same place and run along t

Vikentia [17]

Answer:

The Distance cover by both the Runners is same = 10 miles

Step-by-step explanation:

According to question ,

The Speed of first runners (S 1) = 5 miles per hour

The speed of second runners (S 2) = 4 miles per hour

Let The Time taken by First runner (T 1 ) = T hour

But the second runner arrives half hour after the first runner ,

I.e The Time taken by Second runner (T 2) = ( T + $\frac{1}{2}$ )

Now from Distance = Speed × Time

Since both the runners start from same place and run along the same trail

SO ,Both the Distance cover by both are same , D 1 = D 2

i.e Speed 1 × Time 1 = Speed 2 × Time 2

5 mph × T = 4 mph × ( T + $\frac{1}{2}$ )

5 T = 4 T + ( 4 × $\frac{1}{2}$ )

Or, 5 T - 4 T = 2

∴ T = 2 hour ,

Time take by first = T1 = T = 2 hour

Time take by second = T2 = T + $\frac{1}{2}$ = (2 + $\frac{1}{2}$ )hour = $\frac{5}{2}$

Now the Distance cover = Speed × Time

Distance (D1) = 5 mph × 2 hour = 10 mile

And Distance (D2) = 4 mph × $\frac{5}{2}$ = 10 miles

Hence, As The Distance cover by both the Runners is same = 10 miles Answer

5 0

3 years ago

In ΔEFG, f = 1.2 inches, ∠E=55° and ∠F=109°. Find the length of e, to the nearest 10th of an inch.

Alekssandra [29.7K]

Answer:

e = 1.04

Step-by-step explanation:

To find e, we apply the sine rule

e/sineE = f/sineF

e/sine55 = 1.2/sine109

e/0.8192 = 1.2/0.9455

0.9455e = 1.2 x 0.8192

e = 0.9830/0.9455

e = 1.0397

to nearest tenth = 1.04inch

3 0

3 years ago

Thank you:)))))))))))))

Anastasy [175]

Your welcomeeeeeeeeeee

3 0

3 years ago

3 csc^2(2x) + 2 cosec 2x = 1-cot^2(2x)

asambeis [7]

I am assuming you want to solve for x:-

Now cosec^2 2x = 1 - cot^2 2x so the equation becomes

3 cosec^2(2x) + 2 cosec 2x = cosec^2 2x

2 cosec^2 2x + 2 cosec 2x = 0

2 cosec 2x ( cosec 2x + 1) = 0

so 2 cosec 2x = 0 or cosec 2x = -1

cosec 2x = 0 or cosec 2x = -1

cosec 2x = 0 is indeterminate so we ignore the first one

cosec 2x = -1 can be written as 1 / sin 2x = -1

so sin 2x = -1

giving 2x = 270 degrees

Therefore x = 135 degrees answer

3 0

3 years ago