Answer: A
Step-by-step explanation:
just took it
Answer: I assume the radius is 1/2 the base of 6 in.
r = 3 ft
h = 10 ft
s = 10.4403 ft
V = 94.2478 ft³
L = 98.3976 ft²
B = 28.2743 ft²
A = 126.672 ft²
r = radius
h = height
s = slant height
V = volume
L = lateral surface area
<span>B = base surface area </span>
A = total surface area
π<span> = pi = 3.14159</span>
<span>√ = square root</span>
Answer:
13ft
Step-by-step explanation:
Kindly find attached a rough draft of the situation.
Step one:
Given data
The length of the slide represents the
Hypotenuse of the situation on the rough sketch
Angle =33°
Required
The height of the ladder which is the adjacent of the rough sketch represented by x
Step two:
Applying SOH CAH TOA
Cos θ= adj/hyp
Cos 33=x/15
0.84=x/15
Cross multiplying
x=0.84*15
x=12.6
To the nearest foot the ladder is 13ft tall
Tan 18 = opposite side/adjacent side
0.3249 = 4/adjacent side
and adjacent side = 4/0.3249 = 12.31
Now let's apply Pythagoras to find x
4² + 12.31² = x²
16 + 151.55 = x² and x² = 167.55
Then x = √167.55 and x = 12.94 ≈ 13
Answer:
R = 112, S = 64, T = 58, U = 126
Step-by-step explanation:
Quadrilateral ABCD is reflected to create quadrilateral RSTU
The angles are all the same
Since a quadrilateral equals up to 360
112+64+58=234
360-234=126