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nataly862011 [7]
3 years ago
14

Is there a relationship between the distance and the sum? Is there a relationship between the distance and the difference? A 5-c

olumn table with 3 rows. Column 1 is labeled a with entries 1, 4, negative 6. Column 2 is labeled b with entries 2, negative 1, negative 3. Column 3 is labeled a + b with entries 3, 3, negative 9. Column 4 is labeled a minus b with entries negative 1, 5, negative 3. Column 5 is labeled Distance with entries 1 unit, 5 units, 3 units. Which describes the relationship between the distance and the difference? The distance is always the opposite of the difference. The distance is exactly the difference. The distance is the absolute value of the difference. The distance is not related to difference.
Mathematics
1 answer:
kifflom [539]3 years ago
3 1

Answer:.

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Step-by-step explanation:

k

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Use the formula d=rt Find t for r = 48.3 m/h and d = 545.79 m.
djyliett [7]
D = 545.79
r = 48.3

Plug in numbers to corresponding variables

545.79 = t(48.3)

Isolate the t, divide 48.3 from both sides

(545.79)/48.3 = 48.3t/48.3

t = 545.79/48.3
t = 11.3

t = A) 11.3 h

hope this helps
8 0
3 years ago
Which is the graph of f(c=(x+3)(x-2)?
Sloan [31]

Answer:


Step-by-step explanation: f(x)=(-3,0), (-0.5,-6.25), (0,-6), (2,0);


4 0
3 years ago
The measure of two supplementary angles are x+10 and 2x-5. Find the values of x and then find the angles
astra-53 [7]

Answer:

  68 1/3, 111 2/3

Step-by-step explanation:

The sum of two supplementary angles is 180°, so ...

  (x +10) +(2x -5) = 180

  3x +5 = 180 . . . . . collect terms

  x +5/3 = 60 . . . . . divide by 3

  x = 58 1/3 . . . . . . . subtract 5/3

The first angle is ...

  x +10 = 58 1/3 +10 = 68 1/3

The second angle is ...

  2x -5 = 2(58 1/3) -5 = 116 2/3 -5 = 111 2/3

The angles measure 68 1/3 and 111 2/3.

6 0
3 years ago
if Pentagon ABCDE is rotated 180 clockwise to 8 pentagon a b c d and e the coordinates for a will be what
11111nata11111 [884]
 <span>Point A with coordinates (x,y) rotated 180 degrees around O gives point A' with coordinates (-x,-y). 
Hope this helps :D

</span>

3 0
3 years ago
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
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