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tensa zangetsu [6.8K]
2 years ago
8

Which point is located in Quadrant III ?

Mathematics
1 answer:
Firdavs [7]2 years ago
3 0

Answer:

here you go :)

Quadrant lll is always both negative so the answer is (-1/2, -1/4)

Step-by-step explanation:

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Solve for x.<br> 3x + 4x = 14<br> X =<br><br> please explain how you got the answer too
Komok [63]
X=2
You add 3x and 4x which is 7x then divide 14 by 7 which is 2
5 0
3 years ago
A triangle has a height of 15 in. and a area of 120 in. What is the length of it's base?
jek_recluse [69]

Answer:

b=16

Step-by-step explanation:

Formula~ 1/2*b*h

1/2*15*b=120

7.5b=120

b=120/7.5

b=16

(you can substitute the value to check-i've done it below)

1/2*16*15=?

if you work it out, the ans will be 120, therefore the ans is correct!

7 0
3 years ago
Subtract:(40+9)-(30+2)
Georgia [21]

Answer:

17

Step-by-step explanation:

49-32=17

Cud u make me brainliest? Im desperate. Thanks!

Hope this helps!

4 0
3 years ago
Read 2 more answers
1.6 liters of drink were equally distributed into 20 cups how many liters of drink would be in each cup
zimovet [89]

Answer:

0.08

Step-by-step explanation:

1.6 liters of the drink was distributed in 20 cups

The litres of drink in each cup can be calculated as follows

= 1.6/20

= 0.08

Hence 0.08 liters of drink would be in each cup

6 0
3 years ago
The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in
Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 64 inches

           \sigma = standard deviation = 4 inches

           n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{63-64}{\frac{4}{\sqrt{4} } } ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

                                                        = 1 - 0.69146 = 0.30854

Hence, it is 30.85%  likely that average height would be shorter than 63 inches.

7 0
3 years ago
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