Answer:
3
Step-by-step explanation:
Hope this helps!
Answer:
The inequality describing the situation is:
![7b+9u>1500](https://tex.z-dn.net/?f=7b%2B9u%3E1500)
Step-by-step explanation:
Joe works as a busboy at the rate of = $7 per hour
Let the number of hours he works as a bus boy this month be =
hours
∴ Amount Joe would make this month working as a busboy =![\$7\times b=\$7b](https://tex.z-dn.net/?f=%5C%247%5Ctimes%20b%3D%5C%247b)
Joe works as a theater usher at the rate of = $9 per hour
Let the number of hours he works as a theater usher this month be =
hours
∴ Amount Joe would make this month working as a theater usher =![\$9\times u=\$9u](https://tex.z-dn.net/?f=%5C%249%5Ctimes%20u%3D%5C%249u)
Total amount Joe would make this month =
His goal is earn more than $1500 this month.
∴ The situation can be represented in the following inequality:
![7b+9u>1500](https://tex.z-dn.net/?f=7b%2B9u%3E1500)
Answer:
8 and -2
Step-by-step explanation:
Let the numbers be l and s.
We have equations:
l = 5s + 18
3l + 4s = 16
Solve for s by substituting l into the second equation:
3(5s + 18) + 4s = 16
15s + 54 + 4s = 16
19s = 16 - 54
19s = -38
s = -38/19
s = -2
Find the value of l:
l = 5(-2) + 18
l = -10 + 18
l = 8
Answer: Area of ΔABC is 2.25x the area of ΔDEF.
Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as
![A=\frac{\sqrt{3} }{4} a^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%20a%5E%7B2%7D)
with a as side of the triangle.
Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:
a₁ = 1.2a
Then, its area is
![A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}](https://tex.z-dn.net/?f=A_%7B1%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%281.2a%29%5E%7B2%7D)
![A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}](https://tex.z-dn.net/?f=A_%7B1%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D1.44a%5E%7B2%7D)
Triangle DEF is 20% smaller than the original, which means its side is:
a₂ = 0.8a
So, area is
![A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%20%280.8a%29%5E%7B2%7D)
![A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%200.64a%5E%7B2%7D)
Now, comparing areas:
![\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )](https://tex.z-dn.net/?f=%5Cfrac%7BA_%7B1%7D%7D%7BA_%7B2%7D%7D%3D%20%28%5Cfrac%7B%5Csqrt%7B3%7D.1.44a%5E%7B2%7D%20%7D%7B4%7D%29%28%5Cfrac%7B4%7D%7B%5Csqrt%7B3%7D.0.64a%5E%7B2%7D%20%7D%20%29)
2.25
<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>
To get to simplest form find the greatest common factor, or the gcf, of both numbers. To do that find all of the factors and find the one with the highest value both numbers share. So 30 would have factors of 1, 2, 3, 5, 6, 10, 15, and 30, and 42 would have the factors of 1, 2, 3, 6, 7, 14, 21, and 42. Both numbers share the factors of 1, 2, 3, and 6 so the gcf is 6. Now divide both numbers by six to get your answer.
Answer: 5/7