Ask question

Ask question

All categories

2 years ago

14

Choose the correct graph of the function y=√x+1.

2 answers:

Katen [24]2 years ago

4 0

Answer:

[A}

Step-by-step explanation:

Graph using the end point and a few selected points.

x y

0 1

1 2

2 2.41

Graph also below:

ELEN [110]2 years ago

4 0

Find y intercept

$\\ \rm\rightarrowtail y=\sqrt{x}+1$

$\\ \rm\rightarrowtail y=0+1=1$

y intercept=(0,1)

Option A

You might be interested in

A $950 deposit for 18 years compounded at<br> an annual interest rate of 2.21%

pantera1 [17]

Answer: 1408.01$

Step-by-step explanation: Use the compound interest formula P*(1+r)^n Where P is the initial value, r is the interest rate, and n is the number of periods

7 0

3 years ago

In an examination, 50%examinees got grade 'A' in mathematics, 75% got grade 'A' in Science, and 35 students got grade 'A' in bot

jasenka [17]

Answer:

15

Step-by-step explanation:

yes it is subtracting by 75-35 then we got the answer who got A in the science only

3 0

2 years ago

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

3 years ago

Find each missing measure <br> Help please

skad [1K]

Angle m and n are 76 P Q and R are 60

7 0

3 years ago

Find the slope of the line segment that joints the points A(2, -8) and B(-1, 16)

Karo-lina-s [1.5K]

We need to use the Point slope formula to find the slope so we label
(2 , -8);(-1 , 16) subtract
x1 y1 x2 y2. y2-y1/x2-x1
16-(-8)/-1-2 = 24/-3 = -8
meaning the slope of this line is (-8)

8 0

3 years ago