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Jet001 [13]
3 years ago
15

Select all polynomial expressions that are equivalent to 6X^4 + 4X^3 - 7X^2 + 5X +8.

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
The answer is b, c and e
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What is equivalent to (3w-8) -4 (2w+3)
Marysya12 [62]

Answer:

-5w-20 or -5(w+4)

Step-by-step explanation:

(3w-8)-4(2w+3)

3w-8-8w-12

3w-8w-8-12

-5w-8-12

-5w-20

8 0
3 years ago
1) Which number has the<br> least value?<br> A. 87.4<br> B. 7.48<br> C. 8.74<br> D. 4.78
lutik1710 [3]
D has the least value
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X=<br><br> a) 80<br> b) 90<br> c) 100
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The diameter is 80 or the first answer
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4 years ago
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Find the area of the shape
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Answer: The area of the shape is 180 mm


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3 years ago
1. Determine the discriminant and nature of roots of each quadratic equation.
Fiesta28 [93]

Answer:

Please check the explanation.

Step-by-step explanation:

The general quadratic equation is

ax²+bx+c=0

The discriminant = D = b² - 4ac

When b² - 4ac = 0 there is one real root.

When b² - 4ac > 0 there are two real roots.

When b² - 4ac < 0 there are two complex roots.

1) x² -6x + 9=0

On comparing with given quadratic equation x² -6x + 9=0

a = 1, b=-6, c=9

D = b² - 4ac

   = (-6)² - 4(1)(9)

   = 36 - 36

   = 0

D = 0

Thus, there is one real root of quadratic equation x² -6x + 9=0.

2) x² -4x + 3=0

On comparing with given quadratic equation x² -4x + 3=0

a = 1, b=-4, c=3

D = b² - 4ac

   = (-4)² - 4(1)(3)

   = 16 - 12

   = 4

D > 0

Thus, there are two real roots of quadratic equation x² -4x + 3=0.

3)  x² -7x - 4=0

On comparing with given quadratic equation x² -7x - 4=0

a = 1, b=-7, c=-4

D = b² - 4ac

   = (-7)² - 4(1)(-4)

   = 49 + 16

   = 65

D > 0

Thus, there are two real roots of quadratic equation x² -7x - 4=0

4)  2x² +3x +5=0

On comparing with given quadratic equation 2x² +3x +5=0

a = 2, b=3, c=5

D = b² - 4ac

   = (3)² - 4(2)(5)

   = 9 - 40

   = -31

D < 0

Thus, there are two complex roots of quadratic equation 2x² +3x +5=0

8 0
4 years ago
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