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Ludmilka [50]
2 years ago
15

B. What can CRISPR do to our DNA?

Biology
1 answer:
Elina [12.6K]2 years ago
8 0
C.it changes DNA,but it is random
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3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
konstantin123 [22]

Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
  • Insolation energy is 800 calories/cm2/day
  • % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

8 0
3 years ago
3. In centaurs, the allele for curly tails (T) is incompletely dominant to the allele for straight tails (t). The hybrid genotyp
Reptile [31]

Answer:

a. Determine the allele frequencies of:

f(T) = 0.485 ≅ 0.48

f(t) = 0.515 ≅ 0.52

b. Determine the genotype frequencies of the exposed generation

  • F (TT) = 0.21
  • F (Tt) = 0.55
  • F (tt) = 0.24

the genotype frequencies of the next generation

  • F(TT) = 0.23
  • F(Tt) = 0.5
  • F(tt) = 0.27

Explanation:

Due to technical problems, you will find the complete answer and explanation in the attached files

Download pdf
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