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lara [203]
3 years ago
12

During Diwali, candles are lit all around the country in celebration. How many candles would need to be lit in a 40 x 40 meter s

quare area in order for an astronaut in the International Space Station (400 kilometers above ground) to see a spot of light which is as bright as a single candle at 100 meters?
Any answer within 10% of the correct answer is accepted. Ignore atmospheric effects for simplicity.

Mathematics
1 answer:
Bond [772]3 years ago
7 0

Answer:

i download mo yong gautmath

Step-by-step explanation:

masasagot yan lahat ng gautmath

You might be interested in
7 - 8x + 22<br> What does X equal!<br> x =?
VashaNatasha [74]

Answer: x = -3.625 or -29/8

Step-by-step explanation:

7-8x+22

1. -Set it equal to 0.

7-8x+22=0

2. Subtract 7 and 22 from both the left and right sides.

7-8x+22=0

-7 -22      -7 -22

8x = -29

4. Divide both sides by 8.

8x=-29

8       8

x= -3.625

Leave it in fraction form if decimal is unacceptable.

hope this helps.

3 0
4 years ago
If the legs of an isosceles right triangle have a length of 15 StartRoot 2 EndRoot ft, what is the length of the hypotenuse?
lorasvet [3.4K]

Answer:

30 ft

Step-by-step explanation:

a² + b² = c²

(15sqrt(2))² + (15sqrt(2))² = c²

225 * 2 + 225 * 2 = c²

c² = 900

c = sqrt(900)

c = 30

Answer: 30 ft

4 0
3 years ago
Read 2 more answers
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
A cell phone tower covers a circular area with a radius of 15 miles. You are at a location that is 11 miles west and 12 miles so
Murljashka [212]

Answer:

No you do not.

This is because we can use Pythagoras Theorem to show that our location sits outside the 15 mile radius of the cell tower.

To work is out you would write the equation

{11}^{2}  +  {12}^{2}  = 265

Then to work out the Hypotheses you would

\sqrt{265}  = 16.2788205961

Which proves that the location is outside of the 15 Mile radius of the cell tower.

3 0
3 years ago
PLZZZ HELP ME 10 PTSS
Anestetic [448]

Answer:

5 31/ 30 or 6 1/30

Step-by-step explanation:

I wish this helped you

5 0
3 years ago
Read 2 more answers
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