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VLD [36.1K]
3 years ago
10

205,769,205,796 + 1,784,521,794

Mathematics
2 answers:
Olin [163]3 years ago
6 0

Answer:

207553727590

Step-by-step explanation:

lol lol lol lol lol lol lol

meriva3 years ago
6 0

Answer:

Hello, there!

<h2>Your Question↓</h2><h3>  what is 205,769,205,796 + 1,784,521,794</h3><h2>Answer↓</h2>

207,553,727,590 is correct!

Therefore, I hope this Helps!

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A realtor sold a home for ​$341,100 The commission was 4​% of the sale​ price; however, the realtor receives only 60% of the com
Pepsi [2]

Answer:

The relator recived $8,186.4

Step-by-step explanation:

What you have to do is find the 60% of the commission. Commission is 4% of $341,100 (100%)

First do a cross multiplication to find 4% of $341,100

100% ___ $341,100

4%______x:

x=(4*341,100)/100=13,644

So, the 4% of $341,100 is $13,466

Now you have to find the 60% of $13,466

100% ___ $13,466

60%______x:

x=(60*13,466)/100=8,186.4

The answer is: $8,186.4

3 0
3 years ago
The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth
dexar [7]
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10  OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B
5 0
3 years ago
What is the value of x? 1 2 x + 2 = x - 1 4 A) - 2 9 B) - 9 2 C) 1 9 D) 9 2
Volgvan
X=1.3
Hope this helps I not I’m truly sorry
6 0
3 years ago
T had 53,790 miles onit. They had the car for 8.25 years. On average, how many miles did they drive per year?
liq [111]

Answer: ‭6,520‬ miles per year

Step-by-step explanation:

They had driven the car for 53,790 miles in 8.25 years.

The average number of number of miles driven per year is:

= 53,790 / 8.25 years

= ‭6,520‬ miles per year

<em>They drove an average of ‭6,520‬ miles per year.</em>

7 0
2 years ago
Nine voltage measurements in a circuit have produced the following values: 12.09, 12.05, 11.94, 11.99, 12.12, 12.05, 12.02, 11.9
Debora [2.8K]

Answer:

we can not reject any value

Step-by-step explanation: From data we can test the highest and the lowest value to evaluate if one of these values are out of certain confidence Interval

If we established CI = 95 % then  α = 5 % and  α/2 = 0,025

From data we find the mean of the values

μ₀  = 12,03   and σ = 0,07

From z table we find z score for 0,025 is  z(c) = ± 1,96

So limits of our CI are:

12,03 + 1,96 =  13,99

12,03 - 1,96 = 10,07

And all our values are within  ( 10,07 , 13,99)

So we can not reject any value

4 0
3 years ago
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