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irakobra [83]
3 years ago
11

Which ordered pair represent solutions to the linear inequality below. Check all that apply. x - 4y < -12 (-8,-3) (-12,0) (-7

,9) (3,5) (1,-8) (-4,2)
Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

Step-by-step explanation:

x y Result <= -12?

-8 -3 4 NO

-12 0 -12 YES

-7 9 -43 YES

3 5 -17 YES

1 -8 33 NO

-4 2 -12 YES

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Find the lowest common multiple of 8 12 18 by prime factories​
Crank

Step-by-step explanation:

8=1,2,4,8.

12=1,2,3,4,6.

18=1,2,3,6,9.

so 2 is common and lowest in everyone.

answer is 2

5 0
3 years ago
Given a circle with a diameter of 4, which equation expresses π as the ratio of the circumference of a circle to its diameter?
sashaice [31]
4*pi=C
is the formula (d*pi=C)
4 0
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Read 2 more answers
Solve for x: 81 ^-2 : 729 ^1-X = 9 ^2x​
34kurt

Answer:

x=0

Step-by-step explanation:

(1): "^-2" was replaced by "^(-2)".

rearrange the equation: x/81^(-2)/729^1-x-(9^2*x)=0

STEP

1

:

1.1 9 = 32

(9)2 = (32)2 = 34

Equation at the end of step

1

:

x

(—————— ÷ (7291)-x)-(34•x) = 0

(81-2)

STEP

2

:

2.1 729 = 36

(729)1 = (36)1 = 36

Equation at the end of step

2

:

x

(—————— ÷ 36 - x) - 34x = 0

(81-2)

STEP

3

:

3.1 81 = 34

(81)-2 = (34)(-2) = (3)(-8)

Equation at the end of step

3

:

x

(——————— ÷ 36 - x) - 34x = 0

(3)(-8)

STEP

4

:

1

Divide x by ——

38

Equation at the end of step

4

:

38x

(——— - x) - 34x = 0

36

STEP

5

:

38x

Simplify ———

36

Dividing exponents:

5.1 38 divided by 36 = 3(8 - 6) = 32

Equation at the end of step

5

:

(9x - x) - 34x = 0

STEP

6

:

Equation at the end of step 6

-73x = 0

STEP

7

:

Solving a Single Variable Equation:

7.1 Solve : -73x = 0

Multiply both sides of the equation by (-1) : 73x = 0

Divide both sides of the equation by 73:

x = 0

One solution was found :

x=0

3 0
3 years ago
How do I solve this question?
FrozenT [24]
18
Do u give brainiest?

8 0
3 years ago
X
Vsevolod [243]

Answer: B, D, E

Step-by-step explanation:

Statement 1 cannot be true because f(1)<0.

Statement 2 might be true.

Statement 3 cannot be true because if f is continuous, then for some value between -1 and 0, f(x) is positive by the Intermediate Value Theorem.

Statement 4 might be true.

Statement 5 might be true

6 0
2 years ago
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