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Arada [10]
3 years ago
7

Will give brainliest answer

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

X times0.16-x times c=p

Step-by-step explanation:

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Reika [66]
7033/10000 is the answer you're looking for
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For one Geometry test, Nancy correctly answered 18 questions. These correct answers gave her a percent score of 72%. In total, h
Brrunno [24]

Answer:

25 questions.

Step-by-step explanation:

Correct answer = 18

The percent score of the correct answers is 72%.

Let there are x questions in the test. So,

According to the given condition,

72\%\ of\ x=18\\\\\dfrac{72}{100}x=18\\\\x=\dfrac{18\times 100}{72}\\\\x=25

Hence, there were 25 questions in the geometry test.

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If the shape of an object changes the perimeter will always change true or false
Ugo [173]

The answer is false due to the object is changes shape not size

6 0
3 years ago
An ant has a mass of approximately 4 × 10–3 grams and an elephant has a mass of approximately 8 x 106 grams. About how many time
Butoxors [25]
Ant's mass: 4 x 10 - 3
Elephant's mass: 8 x 106

First, we should evaluate these expressions by using PEMDAS. PEMDAS stands for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction. From P to S is the order that we must follow these steps.

So first for the ant's mass, we have to multiply first since the M comes before the S, resulting in 40 - 3 grams.
Next we have to subtract, leading us to getting 37.

For the elephant since there is only one operation, all we have to do is multiply, which equals 848.

In order to see how many times larger the elephant is than the ant, we have to divide the elephant's mass by the ant's.
848/37 = 22.9

Since you only want an approximate answer, you can put down 23 or even go a bit more vague and put down 20.
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3 years ago
HOW can a table be used to find the rate of change and the initial value?
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The data will display the data. When you look at the data and see the change in the data, that is how you can see what is the rate of change. You find the initial volume by using the data from the chart as if you was just reading the biggest of all the value. 
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