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Alla [95]
10 months ago
10

Michelle drew a scale drawing of a swimming pool she used the scale 14 millimeters 5 meters in the drawing the pool is 42 millim

eters wide what is the width of the actual pool
Mathematics
1 answer:
Lera25 [3.4K]10 months ago
6 0

EXPLANATION

Let's see the facts:

The scale is---> 14 milimeters ----> 5 meters

Width = 42 milimeters

Applying the unitary method, the actual width of the pool is:

Actual_{}width=42\text{ mm}\cdot\frac{5m}{14\text{ mm}}=15m

The width of the pool is 15m

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The length of the rectangle = 16 meters

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<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

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<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

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<u><em>Step 4</em></u><em> :</em>

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Factorizing -546 as -26\times21

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The sum of -26 + 21 = -5

<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

The width of the rectangle = 10.5 meters

The length of the rectangle = 2x-5

                                                = 2(10.5) - 5

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