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3 years ago

8) 8 kg of apples cost Rs.800, what is the cost of 15 kg of apples?

Mathematics

1 answer:

Rama09 [41]3 years ago

8 0

Answer: 4

Step-by-step explanation:Using unitary method :-

5 kg apple → 600 Rs

1 kg apple →

600

= 120 Rs

27 kg apple →120×27=3240 Rs

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The exppreson of 10x^2-7

erica [24]

The complete question is :

Question: What is the coefficient in the expression 10x²-7?

The coefficient in the expression $10x^{2} -7$ is 10

<h3>What is Coefficient?</h3>

A numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

According to the question,

The expression given is $10x^{2} -7$

The variable given is x

We need to find the coefficient in the expression.

In the given expression x is the variable and the number before the x is coefficient which is 10 .

Hence the coefficient in the expression is 10.

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S Rob and Bob together scored 88

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3 years ago

Find the angle to the nearest degree. * sin-10.5166 1 31.1° 58.9° 0.5°

Mice21 [21]

Given:

The given inverse trigonometric term is:

$\sin^{-1}(0.5166)$

To find:

The value given inverse trigonometric term.

Solution:

We have,

$\sin^{-1}(0.5166)$

Using the calculator, we get

$\sin^{-1}(0.5166)=31.10446$

$\sin^{-1}(0.5166)\approx 31.1^{\circ}$

The value of given term is 31.1°.

Therefore, the correct option is B.

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3 years ago

What are the domain and range of the function? f(x)=−3/5x^3

vichka [17]

f(x)= −3/5x³

The domain is all values x can be. There are no restrictions on x. it can be any real number (-∞ , ∞)

The range is all values y can be. There are noi restrictions on y either because the function is odd. y is (-∞ , ∞)

The best answer is D.
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range (-∞, 0] ∪[0, ∞)

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3 years ago

Write the trigonometric expression sin(sin−1u−tan−1v) as an algebraic expression in u and v. Assume that the variables u and v r

igomit [66]

Answer:

[u – v√(1 – u²)]/√(1 + v²)

Step-by-step explanation:

Let sin^-1(u) = A, therefore sinA = u.

We know that sin(theta) = opposite/hypothenuse

Therefore, sinA = u/1 and u is the opposite side to angle A while 1 is the hypotenuse. Draw an acute triangle placing u opposite to angle A and 1 as the hypotenuse. By Pythagoras theorem the adjacent would be √(1 – u²).

By doing this, it means cosA = adjacent/hypotenuse = √(1 – u²)/1 = √(1 – u²)

Also, let tan^-1(v) = B, therefore tanB = v.

We know that tan(theta) = opposite/adjacent

Therefore, tanB = v/1 and v is the opposite side to angle B while 1 is the adjacent. Draw an acute triangle placing v opposite to angle B and 1 as the adjacent. By Pythagoras theorem the hypothenuse would be √(1 + v²).

Therefore, sinB = opposite/hypotenuse = v/√(1 + v²) and cosB = adjacent/hypotenuse = 1/√(1 + v²)

Now,

sin[sin^–1(u) – tan^–1(v)] =

sin(A – B) =

sinAcosB – sinBcosA =

u[1/√(1 + v²)] – [v/√(1 + v²)][√(1 – u²)] =

[u/√(1 + v²)] – [v√(1 – u²)/√1 + v²)] =

[u – v√(1 – u²)]/√(1 + v²).

8 0

3 years ago

8) 8 kg of apples cost Rs.800, what is the cost of 15 kg of apples?​

8) 8 kg of apples cost Rs.800, what is the cost of 15 kg of apples?