The correct option is ARGON.
To quickly find out the element that is been described by the electronic configuration, write down and add together all the index figures in the electronic configuration. The index figures in the above electronic configuration are 2, 2, 6, 2 and 6. If you add all these figures together, you will get 18 and the element that has the atomic number of 18 is argon.
The environment would have most likely been covered in deep water such as in a lake or swamp. One with clay particle and other fine particle sediments.
Answer:
Darmstadtium
Explanation:
An element with the electronic configuration 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d⁸ has 110 electrons in its electron shells.
Since the element is a neutral atom, this number is also equal to its atomic number. Therefore, its atomic number is 110.
The element in the period table that has an atomic number of 110 is Darmstadtium, a d-block element, thus a transittion metal. It also belong to period 7 in the Periodic table of elements.
Answer:
0.01 M
Explanation:
The chemist is performing a serial dilution in order tyo obtain the calibration curve for the instrument.
First we must obtain the concentration of the solution in the 250ml flask from
C1V1 = C2V2
Where;
C1 = concentration of the stock solution
V1 = volume of the stock solution
C2 = concentration of the diluted solution
V2= volume of the diluted solution
2.61 × 10 = C2 × 250
C2 = 2.61 × 10/250
C2 = 0.1 M
Hence for solution in 100ml flask;
0.1 × 10 = C2 × 100
C2 = 0.1 × 10/100
C2 = 0.01 M
The question is incomplete, the question is;
Which drawing best accounts for the polarity of methanol, CH3OH, and the bond polarities that make a major contribution to the overall molecular polarity?
A) drawing (1) B) drawing (2)
D) drawing (4) C) drawing (3)
Answer:
B) drawing (2)
Explanation:
In Chemistry, the direction of dipole is shown from positive end to negative end.
The image that contains the options in the question asked has been attached.
We can see in image 2 that the oxygen atom was correctly designated as the negative end of the dipole while the carbon and hydrogen atoms were each designated as positive ends of the dipole in accordance with the magnitude of electronegativity difference between the two atoms. The net dipole moment is now taken in the direction shown in image 2. This is the correct answer.
