Answer:
The correct answer is 1 NADH is generated by the oxidation of glucose-6-phosphate.
Explanation:
Pentose phosphate pathway deals with the utilization of glucose-6-phosphate by oxidation process to form 6-phosphogluconolactone by the catalytic activity of glucose-6-phosphate dehydrogenese.
This enzyme need NAD+ as co enzyme which get reduced to generate NADH.
Answer:
424 mol
Explanation:
Step 1: Given data
Number of atoms of Neon: 2.55 × 10²⁶ atoms
Step 2: Calculate the number of moles corresponding to 2.55 × 10²⁶ atoms of Neon
In order to convert atoms into moles, we need a conversion factor, which is Avogadro's number: there are 6.02 × 10²³ atoms of Neon in 1 mole of atoms of Neon.
2.55 × 10²⁶ atoms × (1 mol/6.02 × 10²³ atoms) = 424 mol
Answer:
Electron configuration: [He] 2s²2p⁴
Explanation:
<h3>
Answer:</h3>
132.03 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation for the reaction as;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
- Mass of CO as 84 grams
We are required to calculate the mass of CO₂ that will produced.
<h3>Step 1: Calculate the number of moles of CO</h3>
Moles = Mass ÷ Molar mass
Molar mass of CO = 28.01 g/mol
Therefore;
Moles of CO = 84 g ÷ 28.01 g/mol
= 2.9989 moles
= 3.0 moles
<h3>Step 2: Calculate the number of moles of CO₂</h3>
- From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
- Therefore; the mole ratio of CO to CO₂ is 1 : 1
- Hence; Moles of CO = Moles of CO₂
Moles of CO₂ = 3.0 Moles
But; mass = Moles × molar mass
Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol
= 132.03 g
Hence, the mass of CO₂ produced from the reaction is 132.03 g
The <span> the Brønsted-Lowry acid donates H⁻.
In this reaction Particle that loose H⁺ is A. NH4⁺ ion.</span>