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3 years ago

12

According to uniformitarianism, which statement is true?

2 answers:

Ivenika [448]3 years ago

8 0

If I guess since I’m in AP Biology 2 and we have touched upon that briefly, I would say C.

Deffense [45]3 years ago

8 0

Answer:

C. Weathering, erosion, and uplift occur at the same rates now as they did in the past.

Explanation:

Hello,

In this case, one remembers the concept of uniformitarianism as everything that has been happening at the same rate through the whole geological time scale until the nowadays. In such a way, one concludes everything changes at the same rate all of the time.

In such manner, based on the uniformitarianism, the processes of weathering, erosion, and uplift occur in the present at the same rate as they have been occurring during the earlier years (past), nonetheless, this concept has not been widely adopted, as there are a lot of proofs unvalidating it.

Best regards.

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The average lung capacity of a human is 6.0L.

Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

(c) 8.77 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol$

(b)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol$

(c)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol$

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3 years ago

Assign oxidation numbers to each element in MgSO4. (magnesium sulfate)

hjlf

Answer:

The answer to your question is: letter b Sulphur

Explanation:

Remember that in neutral molecules the sum of the oxidation numbers equals zero.

Mg⁺²S⁺⁶O⁻²₄

Magnesium = +2

Sulphur = +6

Oxygen = -2 x 4 = -8

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