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4 years ago

According to uniformitarianism, which statement is true?

Chemistry

2 answers:

Ivenika [448]4 years ago

8 0

If I guess since I’m in AP Biology 2 and we have touched upon that briefly, I would say C.

Deffense [45]4 years ago

8 0

Answer:

C. Weathering, erosion, and uplift occur at the same rates now as they did in the past.

Explanation:

Hello,

In this case, one remembers the concept of uniformitarianism as everything that has been happening at the same rate through the whole geological time scale until the nowadays. In such a way, one concludes everything changes at the same rate all of the time.

In such manner, based on the uniformitarianism, the processes of weathering, erosion, and uplift occur in the present at the same rate as they have been occurring during the earlier years (past), nonetheless, this concept has not been widely adopted, as there are a lot of proofs unvalidating it.

Best regards.

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The partial pressure of carbon dioxide in air varies with the seasons. Would you expect the partial pressure in the Northern Hem

Stels [109]

Answer:

It will be higher in the summer.

Explanation:

Usually, the winter season is more harsh a weather on leaves than summer because it is wet season and thus has less sunlight and this means there will be less photosynthesis reactions and therefore it means the partial pressure will be lesser here unlike in the summer when it is a more warm and dry weather with sunlight where photosynthesis reactions will be more favorable to occur.

Thus, CO2 which is a great component of photosynthesis is used more in the summer and as such the partial pressure in the summer will be higher.

4 0

3 years ago

Give the name of HI as an acid and as a binary compound

Flura [38]

Answer:

HI is a diatomic molecular compound known as hydrogen iodide or hydroiodic acid. It is a strong acid.

8 0

3 years ago

At STP how many moles or helium would occupy a volume of 12 liters?

butalik [34]

1 mole ------------- 22.4 L ( at STP )
?? mole ---------- 12 L

12 x 1 / 22.4 => 0.5357 moles

hope this helps!

5 0

4 years ago

A piece of copper (12.0 g) is heated to 100.0 °C. A piece of chromium (also 12.0 g) is chilled in an ice bath to 0 °C. The speci

Gennadij [26K]

Answer:

(a) Slightly greater than 20.0 °C

(b) $T_F=293.46K=20.3^oC$

Explanation:

Hello,

In this case, since we are talking about the equilibrium temperature that will be reached when the copper, chromium and water samples get in contact, the following equation is useful to describe such situation:

$\Delta H_{water}+\Delta H_{copper}+\Delta H_{chromium}=0\\$

Thus, in terms of masses, heat capacities and temperatures we consider the final temperature as the unknown:

$m_{water}Cp_{water}(T_F-T_{water})+m_{copper}Cp_{copper}(T_F-T_{copper})+m_{chromium}Cp_{chromium}(T_F-T_{chromium})=0$ In such a way, by knowing that the heat capacities of copper and chromium are 0.386 and 0.45 J/(g°C) respectively, by solving for the equilibrium temperature one has:

$T_F=\frac{m_{water}Cp_{water}T_{water}+m_{Cu}Cp_{Cu}T_{Cu}+m_{Cr}Cp_{Cr}T_{Cr}}{m_{water}Cp_{water}+m_{Cu}Cp_{Cu}+m_{Cr}Cp_{Cr}}$

$T_F=\frac{200.0g*4.184\frac{J}{g*K}* 293.15K+12.0g*0.386\frac{J}{g*K} *373.15K+12.0g*0.45\frac{J}{g*K}*273.15K}{200.0g*4.184\frac{J}{g*K}+12.0g*0.386\frac{J}{g*K} +12.0g*0.45\frac{J}{g*K}}\\\\T_F=293.46K=20.3^oC$

Hence, the resulting temperature of water turns out slightly greater than 20.0 °C.

Best regards.

7 0

3 years ago

I need so much help 50 points!!!!!! complete the graph

sergij07 [2.7K]

Where is the graph at? may you send a picture of it?

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3 years ago