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Vladimir [108]
2 years ago
8

Justin wants to make a scale drawing of his house. His kitchen is a rectangle that is 14m long and 6m wide. He is using a scale

of 1 to 20.
a. Draw the scale drawing of Justin's kitchen. Label the length and the width of the picture in centimeters


b. If Justin has a table that was 1.5m long, what would the size of the table be in the scale drawing?



ANSWER BOTH PARTS PLEASE !!
Mathematics
2 answers:
LenaWriter [7]2 years ago
3 0
You have to draw a line of Justin’s kitchen and then draw his modern table hire an artist to do it for you hope that helps
nika2105 [10]2 years ago
3 0
This is part A I can’t do part B

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20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that
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<u>ANSWER:  </u>

The algebraic expression for number of ribbons is \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into 7\frac{1}{2} inches or 6\frac{3}{4} inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}

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\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}

\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right ]

So, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}

So, the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

Hence, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

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