Answer:
<u>65.4 cubic inches</u>
Step-by-step explanation:
Formula for the volume of a cone :
<u><em>Volume (cone) = 1/3πr²h</em></u>
<u><em /></u>
=============================================================
Given :
⇒ diameter = 5 in. → radius = <u>2.5 in.</u>
⇒ height = <u>10 in.</u>
<u />
===========================================================
Solving :
⇒ Volume (cone) = 1/3 × π × (2.5)² × 10
⇒ Volume (cone) = 62.5π/3
⇒ Volume (cone) = <u>65.4 cubic inches</u>
The normal distribution curve for the problem is shown below
We need to standardise the value X=405.5 by using the formula


We now need to find the probability of z=0.32 by reading the z-table
Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

from the z-table, the reading

gives 0.6255
hence,

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%
7. Four and 7 tenths
8. Twenty two and eighty nine hundredths
9. Forty Five and Three hundred Twenty Nine Thousandths
10.Twenty seven hundredths
0.5(100-30) = 35
Hope this helps............
Answer:
2x "hope this helps"
Step-by-step explanation: