Question

Y'all i need this to be doneee!! Don't answer this quest if you don't know what's the answer.. Thanks!!

Answer 1

Try this option:

I) standart form of quadratic equation is:

ax²+bx+c=0, where a, b and c - numbers.

II) all the answers are provided in the attached picture. Note, the column 'Equation' is missed in the picture.

If it is possible, check the answers in other sources.

Answer 2

Answer:

Standard Form a b c

1. 2x² - x + 5 = 0 2 -1 5
2. x² + 4x - 5 = 0 1 4 -5
3. x² - 3x = 0 1 -3 0
4. y² + y+ 5 = 0 1 1 5
5. 5x² - 7x = 0 5 -7 0
6. 3x² - 2x + 4 = 0 3 -2 4
7. x² + 3x = 0 1 3 0
8. x² - 4x - 5 = 0 1 -4 -5
9. x² + 2x + 8 = 0 1 2 8
10. x² - x + 15 = 0 1 -1 15

Examples to solve some on your own:

Quadratic equations are of the form:

ax² + bx + c = 0

In their standard form you'll have to place the variables in their decreasing order of exponents, like:

• x raised to 2, first
• then x raised to 1
• a finally x raised to 0 (since x⁰ = 1, every constant is assumed to be with x⁰)

In the very first question, we have:

x = 2x² + 5

we'll want 0 on one side and exponents in their decreasing order on the other

taking x to the RHS (it's sign gets reversed, when moving from one side to another)

0 = 2x² - x + 5 . . . . .(¡¡)

so this is the standard form!

comparing this equation with ax² + bx + c = 0 . . . . .(¡)

we get,

• a = 2
• b = -1
• c = 5

(a is with x² in eqn. (¡) and 2 is with x² in eqn. (¡¡) so a will be equal to 2)

In the 10th question:

=> 2x - 5(x + 3) = x(x - 4)

removing the parenthesis:

=> 2x - 5x - 15 = x² - 4x

taking all the terms from LHS to RHS:

=> 0 = x² - 4x -2x + 5x + 15

solving the like terms together:

=> 0 = x² - x + 15 . . . . .(¡¡¡)

that's the standard form!

comparing it with eqn. (¡)

we get,

• a = 1
• b= -1
• c = 15

[If the display of the answer isn't clear, check the attachment]