One leg is horizontal, on the line y=3. Another leg is vertical, on the line x=1. The point where these intersect, D(1, 3) is the vertex of a right angle. Any right triangle inscribed in a circle has its hypotenuse as the diameter of the circle.
Since the triangle is a right triangle, the circumcenter is the midpoint of the hypotenuse: ((8, 3) + (1, -5))/2 = (4.5, -1).
99.69/100=.9969
.9969*20=19.938
Ramon would receive ~ $19.94
Answer:
use the distance formula,
by using it, prove the adjacent sides of the quadrilateral DEFG
hence, DEFG would be a rhombus
Answer:
SAS
Step-by-step explanation:
Given: Two triangles ΔABD and ΔDCA,
We have, AD=AD (normal)
∠A=∠A (Given)
BA=CD (Sides inverse to rise to points are consistently equivalent)
With the SAS rule of congruency,
ΔABD≅ΔDCA
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