The length can be found using the Pythagorean Theorem...

c^2=a^2+b^2 and in this case:

d^2=(dx^2)+(dy^2)

d^2=(3-7)^2+(12-9)^2

d^2=-4^2+3^2

d^2=16+9

d^2=25

d=5

So the length of AB=5 units.

8 0

3 years ago

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Find a center of mass of a thin plate of density delta equals 5δ=5 bounded by the lines y equals xy=x and x equals 0x=0 and the

kow [346]

Answer:

center of mass

X = $\frac{my}{m} = \frac{28}{19}$

Y = $\frac{mx}{m} = \frac{872}{95}$

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = $\frac{152}{3}$ б

Mx = $\frac{6976}{15}$ б

My = $\frac{224}{3}$ б

X = $\frac{my}{m} = \frac{28}{19}$

Y = $\frac{mx}{m} = \frac{872}{95}$

5 0

3 years ago

The expression 9+21 factored using GCF is?

Blizzard [7]

Rewrite and factor 9 and 21;

3•3+3•7= 3(3+7)

GCF for 9 and 21 is 3

8 0

2 years ago

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