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2 years ago

(2) Below is the graph of a function, y = f (x).

Mathematics

1 answer:

Airida [17]2 years ago

3 0

Answer:

Step-by-step explanation:

a. To draw a secant line, just draw a straight line connecting the 2 points at x = 0 and x = 4.

b. The average rate of change of this line is going to be the change in y / the change in x. The equation will be (f(4) - f(0))/(4 - 0) = (0 - 3) / 4 = -3/4.

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A chandelier was marked up 150% from an original purchase cost of $92. Yesterday, Jayce sold the chandelier, earning a 20% commi

tatuchka [14]

Answer:

92 * 1.5 = 138

138* .2 = $27.60

Step-by-step explanation:

4 0

3 years ago

Solve the quadratic equation (x-3)2 = 49

Tresset [83]

27.5, because 27.5-3=24.5 and 24.5x2= 49

3 0

3 years ago

Find the x <br> Please help me and show how you got it :)

Kaylis [27]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

The parallel lines divide the sides proportionally, so ratios of corresponding sides are the same.

(x +5)/15 = (5x +1)/35

Multiplying by 105, we have ...

7(x +5) = 3(5x +1)

7x +35 = 15x +3 . . . . . eliminate parentheses

32 = 8x . . . . . . . . . subtract 7x+3 from both sides

4 = x . . . . . . . . divide by 8

4 0

3 years ago

Danielle earns a 8.25% commission on everything she sells at the electronics store where she works. She also earns a base salary

Mariulka [41]

Answer: her sales last week was $4300.

Step-by-step explanation:

Let x represent her her sales in a week.

Danielle earns a 8.25% commission on everything she sells at the electronics store where she works. This means that the commission she gets if she makes sales of $x is 0.0825x

She also earns a base salary of $675 per week. The expression for the total earnings for a week in which she made sales of $x would be

0.0825x + 675

if her total earnings for last week were $1,029.75, it means that

0.0825x + 675 = 1029.75

0.0825x = 1029.75 - 675

0.0825x = 354.75

x = 354.75/0.0825

x = $4300

3 0

3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago