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3 years ago

I just wanna say i hope your having a good day! and you are enough! keep going u got this!

Mathematics

1 answer:

Vladimir79 [104]3 years ago

8 0

aww,thank you ^^

i hope you're having a good day as well

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ASAP!!!!!!!!!!!!!!!!!!!

steposvetlana [31]

Answer:

V = 2143.57 cm^3

Step-by-step explanation:

We want to find the volume of the sphere

V = 4/3 pi r^3 where r is the radius and pi = 3.14

V = 4/3 ( 3.14) ( 8)^3

V = 2143.57333 cm^3

Rounding to the nearest hundredth

V = 2143.57 cm^3

3 0

3 years ago

Read 2 more answers

2(g+5)=-7-4g+g include instructions plz!

Elza [17]

First distribute the 2, then add 7 to that side, so you have 2g+17=-4g+g , subtract 2g and it should be easy to find from there lol

4 0

3 years ago

Find the least common factor denominator for these two rational 7/x^2 and 7/5x

MAVERICK [17]

X^2 and 5x both have x in common to factor out. To add or subtract them, 5x^2 is the least common denominator .

4 0

3 years ago

ILL GIVE BRAINLIEST I NEED STEP BY STEP EXPLANATION PLZ ITS PAST DUE

AnnyKZ [126]

Answer:

umm why not ask the teacher for help they will help you

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0

2 years ago