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vovangra [49]
3 years ago
5

Find the value of x if 81=3x

Mathematics
2 answers:
Alex Ar [27]3 years ago
4 0

Answer:

<em>here </em><em> </em><em>,</em>

<em>8</em><em>1</em><em>=</em><em>3</em><em>x</em>

<em>or </em><em>,</em><em> </em><em>8</em><em>1</em><em>/</em><em>3</em><em>=</em><em>x</em>

<em>or,</em><em>2</em><em>7</em><em>=</em><em>x</em>

<em>hence </em><em>,</em><em>the </em><em>value </em><em>of </em><em>x=</em><em>2</em><em>7</em>

Colt1911 [192]3 years ago
3 0

Answer:

×=27

Step-by-step explanation:

81/3=3×

27=×

hence

×=27

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Which point is not a solution to the system of inequalities?<br> Thank you:)))
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Step-by-step explanation:

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4 years ago
A store sells two different types of coffee beans; the more expensive one sells for $8 per pound, and the cheaper one sells for
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bearhunter [10]

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3 years ago
What is equivalent to 10x - (5x -1)
Alisiya [41]

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what is equivalent to 10x - (5x -1)

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4 0
3 years ago
Read 2 more answers
Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with
skad [1K]

Parameterize S by the vector function

\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle

The integral of the field over S is then

\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv

\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv

\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}

8 0
2 years ago
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