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3 years ago

Find the value of x if 81=3x

Mathematics

2 answers:

Alex Ar [27]3 years ago

4 0

Answer:

here ,

81=3x

or , 81/3=x

or,27=x

hence ,the value of x=27

Colt1911 [192]3 years ago

3 0

Answer:

×=27

Step-by-step explanation:

81/3=3×

27=×

hence

×=27

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Which point is not a solution to the system of inequalities? Thank you:)))

belka [17]

Answer:

(4, -1) is not a solution to the system

Step-by-step explanation:

The first point: (4,-1) doesn't satisfy the first inequality:

$y>x-5\\(-1) > 4-5\\-1>-1$

since we get to an absurd, because -1 cannot be strictly smaller than -1!

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4 years ago

A store sells two different types of coffee beans; the more expensive one sells for $8 per pound, and the cheaper one sells for

Elena L [17]

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4 years ago

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bearhunter [10]

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3 years ago

What is equivalent to 10x - (5x -1)

Alisiya [41]

Answer:

5x + 1 is the simplest form

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

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2 years ago