Well, first, find-out how fast he was going the first time, by dividing 310 by 5. This gives you 62 mph. Now, divide 403 miles by 62 miles per hour in order to find-out how long it would take him to drive 403 miles, if he is constantly doing 62 mph. Your final answer is six-and-a-half hours.
Answer:
D
Step-by-step explanation:
Let's substitute a for x²:
x^4 - 3x² - 4
a² - 3a - 4
Now, this looks like something that is much more factorisable:
a² - 3a - 4 = (a - 4)(a + 1)
Plug x² back in for a:
(a - 4)(a + 1)
(x² - 4)(x² + 1)
The first one is a difference of squares, which can be factored into:
x² - 4 = (x + 2)(x - 2)
The second one can also be treated as a difference of squares:
x² + 1 = x² - (-1) = (x + √-1)(x - √-1) = (x + i)(x - i)
The answer is (x + 2)(x - 2)(x + i)(x - i), or D.
The last graph is the correct graph for the problem
Answer:
(A)3,500 + 0.06x > 4,000 + 0.04x
Step-by-step explanation:
<u>Jose's Earnings</u>
Monthly Salary = $3,500
6% commission on his sales, x =0.06x
Total = 3500+0.06x
<u>Maris' Earnings</u>
Monthly Salary = $4,000
4% commission on her sales, x =0.04x
Total = 4000+0.04x
If Jose's earnings be greater than Maris' earnings, then:
3500+0.06x > 4000+0.04x
