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-BARSIC- [3]
3 years ago
11

A swimming pool has to be drained for maintenance. The pool is shaped like a cylinder with a diameter of 5 m and a depth of 1.4

m. Suppose water is pumped
out of the pool at a rate of 133
per hour. If the pool starts completely full, how many hours will it take to empty the pool?
Espanol
Use the value 3.14 for #, and round your answer to the nearest hour. Do not round any intermediate computations.

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

8 hours

Step-by-step explanation:

basic equation

Q (flow rate) = V (volume)/ t (time)

so to find the time we just rearrange the equation and become

t = V/Q

V of cylinder

V = πr²T

and r (radius) = ½ diameter

V = 3.14 x 5² x 1.4

V = 109.9 m³

if the Q is 13 m³/hour then

t = 109.9/13 = 8.453 hours

round to nearest hour = 8 hours

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You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the x^2 coefficient is 1, i.e. the equation is written like x^2+bx+c=0, then you can say the following about the coefficients b and c:

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So, for example, if we want an equation whose roots are 4 and -2, we have:

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