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Lemur [1.5K]
2 years ago
10

Need Help fast!!! Please!

Mathematics
2 answers:
uranmaximum [27]2 years ago
6 0

Answer:

the third one

Step-by-step explanation:

because on the first paper the food coloring was always twice as much as the frosting and 100 is two times larger than 50.

Andrej [43]2 years ago
4 0
There should be a question to answer
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(a) Complete the table of values for y- 2x + 5<br> -<br> 0<br> 1<br> 2<br> 1<br> 5<br> Y
maxonik [38]

Answer:

Step-by-step explanation:

I think you meant y = -2x + 5.

x    y = -2x + 5

0                       5

1      -2(1) + 5 =   3

2     -2(2) + 5 =   1

Note that every time you increase x by 1, y decreases by 2.

5 0
2 years ago
A standard deck of 52 cards theses cards are divided into four 13-suits: hearts, clubs, spades, and diamonds find the possibilit
Nikitich [7]

24/52 because there are 6 even number in a 13 card section

2,4,6,8,10,12

and there are four of them so you multiply 6 by 4 to get 24

since you know there are 52 cards then you will place 24 over 52

you can simplify this fraction to 6/13 depending what you want

8 0
3 years ago
Six hundred pictures are taken at a photo shoot. Twelve percent of the pictures are black and white. Which equation can be used
Rainbow [258]

Answer:

the answer is the first and why did you delete my answer

Step-by-step explanation:

7 0
3 years ago
Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
Help help help help help
Irina18 [472]
Sometimes never always always
5 0
2 years ago
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