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Lemur [1.5K]
2 years ago
10

Need Help fast!!! Please!

Mathematics
2 answers:
uranmaximum [27]2 years ago
6 0

Answer:

the third one

Step-by-step explanation:

because on the first paper the food coloring was always twice as much as the frosting and 100 is two times larger than 50.

Andrej [43]2 years ago
4 0
There should be a question to answer
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Type the correct answer in the box. x y 3 10 20 In the table, the relation (x, y) is not a function if the missing value of x is
yan [13]

The relation is <em>not a function</em> if any x-value is repeated.

Assuming you have

(x, y) = (3, 10), (__, 20)

if x = 3, the relation is not a function.

3 0
3 years ago
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What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
Solve for j.<br>-2j + 39 = 111<br>j=<br>​
olga_2 [115]

Answer:

reeeeeerre

Step-by-step explanation:

4 0
2 years ago
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What is the equation of the line that passes through the point (6, 3) and has a slope of -2?
tekilochka [14]

We know the equation of a line is y=mx+b. We know the slope (m) is -2 and all we need is the intercept (b).

Since we know one point, we can plug in 6 for x and 3 for y (along with -2 for m) in our equation and then solve for b.

3= -2*6 + b

3= -12 + b

15 = b

Since we now know the intercept we can now write our equation:

y= -2x + 15

3 0
3 years ago
The coordinates of point A are (6, 2). The coordinates of point B are (2, 6). AB¯¯¯¯¯is transformed to form ​A′B′¯¯¯¯¯¯¯​, shown
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Answer:  

​AB¯¯¯¯¯​ is reflected across the y- axis to form A′B′¯¯¯¯¯¯¯​ .

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