Answer:
16
Step-by-step explanation:
How many times more intense is an earthquake measuring 6.8 on the Richter scale than one measuring 5.6?
Given:
Earthquake 1 : magnitude = 6.8
Earthquake 2: magnitude = 5.6
The intensity of an earthquake
I1 / I2
log I1 /s = 6.8
log I2 /s = 5.6
(log I2 /s) - (log I1 /s) = 6.8 - 5.6
(log I2 /s) - (log I1 /s) = 1.2
log(I2 / I1) = 1.2
I2 / I1 = 10^1.2
I2 / I1 = 15.8489
= 16
6.8 earthquake is about 16 times more intense than earthquake measuring 5.6
Divide 24 by 8: 3. Then multiply that number by 5: 15
5/8 of 24 =15
Okay, so the first thing we have to do is take 6ft and convert it into inches so we get the equation (6x12)+6 6 times 12 is 72 so that gives us 72in plus 6 which is 78 and with that answer we take 78in and divide it by 6.17 which is 12.18. She has a long arm measuring i while feet and 18 inches lol
Answer:
72 mins
Step-by-step explanation:
24/4 = 6
So each poster take 6 mins to decorate
12 x 6 = 72
Answer:
vw equals 48 or w equals 24 and v equals 24
Step-by-step explanation: