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Lesechka [4]
3 years ago
8

A can of soda weighs 4.7 newtons (N) on Earth's surface. What will it weigh on Planet X where the acceleration due to gravity is

1.82 meters per second^2?
Physics
1 answer:
mylen [45]3 years ago
3 0

Explanation:

The mass of the soda can is

m = \dfrac{W}{g} = \dfrac{4.7\:\text{N}}{9.8\:\text{m/s}^2} = 0.48\:\text{kg}

The weight of this same soda can on Planet X is

W = mg_p = (0.48\:\text{kg})(1.82\:\text{m/s}^2) = 0.87\:\text{N}

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Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of eac
grin007 [14]

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

                                     F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

      mg(1 - sinθ - μcosθ) = 2ma

      ½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

8 0
3 years ago
Converting 16.2 pounds to 1 newton
laiz [17]

16.2 pounds doesn't convert to 1 newton.
It converts to about  71.1 newtons

1 pound force is the same force as  4.448... newtons (rounded).

7 0
3 years ago
The heating of the lower layer of the atmosphere from radiation absorbed by certain heat- absorbing gasses is called ?
abruzzese [7]
I think you're talking about the 'greenhouse effect'.
8 0
3 years ago
One of the statements below is correct In an ideal system where all forms of friction are ignored?
noname [10]

Answer:

a.

Explanation:

In a perfect system then energy can be changed from Kinetic to Gravitational Potential and vice versa without any losses. A common form of loss would be thermal energy, so b. is not the answer. c. is invalid as we want these 2 forms of energy to be transferred between, and d. is invalid as these statements c and a contradict each other.

3 0
3 years ago
A freight car with a mass of 10 metric tons is rolling at 108 km/h along a level track when it collides with another freight car
Rufina [12.5K]

Answer:

20 metric tons

Explanation:

Using the Principle of Conservation of Linear Momentum which states that the total momentum of a system is constant in any direction in which no external force acts.

momentum before collision= momentum after collision

mathematically expressed as

m1u1 + m2u2 = m1v1+m2v2 =0

where:

m1= mass of rolling freight car = 10 metric tons = 10Mg

1 ton = 1000kg= 1Mg

u1 =initial velocity of freight car = 108km/h,

m2 = mass of stationary freight car = ?, this the unknown we are finding

u2 = initial velocity of

m2 = 0, because it is at rest,

v1= final velocity of m1,

v2= final velocity of m2

since they move together in the same direction they share a common final velocity as such

v1=v2= 36km/h

substituting valves in expression give

m1u1 + m2u2 = m1v1 + m2v2= 0

10Mgx 108km/hr + m2 x 0 = 10Mg x 36km/h + m2x36km/h

1080( Mg x km/hr) + 0 = 360 (Mg x Km/h) + 36m2 (km/h)

1080 (Mgx km/hr) - 360(Mg x km/h) = 36m2 (km/h)

720(Mg x km/h) = 36m2 (km/h)

divide both side by  36 (km/h) gives

m2 = 20Mg =20 metric tons

3 0
4 years ago
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