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2 years ago

8

The heating of the lower layer of the atmosphere from radiation absorbed by certain heat- absorbing gasses is called ?

1 answer:

abruzzese [7]2 years ago

8 0

I think you're talking about the 'greenhouse effect'.

You might be interested in

Synchronous communications satellites are placed in a circular orbit that is 3.59 107 m above the surface of the earth. What is

suter [353]

Answer: $0.223 m/s^{2}$

Explanation:

We can solve this with the Law of Universal Gravitation and knowing the acceleration due gravity $g$ of an object above the surface of the planet decreases with the distance (height) of this object from the center of the planet.

Well, according to the law of universal gravitation:

$F=G\frac{m_{E}m}{r^2}$ (1)

Where:

$F$ is the module of the force exerted between both bodies

$G=6.67(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the gravitational constant

$m_{E}=5.98(10)^{24} kg$ is the mass of the Earth

$m$ are the mass of each communications satellite

$r=R_{E}+h$ is the distance between the center of the Earth and the satellite

$R_{E}=6.38(10)^{6} m$ is the radius of the Earth

$h=3.59(10)^{7} m$ is the height of the satellite, measured from the Earth's surface

On the other hand, we know according to <u>Newton's 2nd law of motion:</u>

$F=mg$ (2)

Combining (1) and (2):

$G\frac{m_{E}m}{r^2}=mg$ (3)

Isolating $g$ :

$g=\frac{G M_{E}}{r^2}$ (4)

Remembering $r=R_{E}+h$ :

$g=\frac{G M_{E}}{(R_{E}+h)^2}$ (5)

$g=\frac{(6.67(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24} kg)}{(6.38(10)^{6} m+3.59(10)^{7} m)^2}$

Finally:

$g=0.223 m/s^{2}$

5 0

2 years ago

Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:

Deffense [45]

Answer:

a) $T=0.01s$

b) $T=0.001s$

c) $T=0.00001s$

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

$T=\frac{1}{f}$

Therefore

a)

For

$T=100 Hz$

$T=\frac{1}{100}$

$T=0.01s$

b)

For

$F=1kHz$

$T=\frac{1}{1000}$

$T=0.001s$

c)

For

$F=100kHz$

$T=\frac{1}{100*100}$

$T=0.00001s$

6 0

2 years ago

An object has a mass of 10 kilograms and is accelerating at 5 m/s/s, what force pushed the object?

Katen [24]

Answer:

force pushed the object = 10 × 5 = 50N

8 0

2 years ago

What type of heat does not require matter?

Lana71 [14]

It would be Thermal Radiation

4 0

2 years ago

Read 2 more answers

Atom in the ground state is said to be

koban [17]

Answer:

Ground-state atom

Explanation:

When an atom is not excited, it is in its ground-state, which we refer as "standard" or "normal" state.

(Hopefully that helped you!)

GOOD LUCK

Astrophysicist Dr. D

3 0

2 years ago