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jasenka [17]
4 years ago
15

The gradient of a displacement-time graph gives

Physics
1 answer:
Drupady [299]4 years ago
7 0

Answer:

Velocity

Explanation:

The gradient= change in velocity

——————————

Change in time

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A block of mass 0.244 kg is placed on top of a light, vertical spring of force constant 4 975 N/m and pushed downward so that th
yuradex [85]

As the spring returns to it's equilibrium position, it performs

1/2 (4975 N/m) (0.097 m)² ≈ 23 J

while the gravitational force (opposing the block's upward motion) performs

-(0.244 kg) g<em> </em>(0.097 m) ≈ -2.3 J

of work on the block. By the work energy theorem, the total work done on the block is equal to the change in its kinetic energy:

23 J - 2.3 J = 1/2 (0.244 kg) v² - 0

where v is the speed of the block at the moment it returns to the equilibrium position. Solve for v :

v² = (23 J - 2.3 J) / (1/2 (0.244 kg))

v = √((23 J - 2.3 J) / (1/2 (0.244 kg)))

v ≈ 44 m/s

After leaving the spring, block is in free fall, and at its maximum height h it has zero vertical velocity.

0² - (44 m/s)² = 2 (-g) h

Solve for h :

h = (44 m/s)² / (2g)

h ≈ 2.3 m

3 0
3 years ago
If the index of refraction for a certain glass is 1.5, and the angle of refraction is 15 degrees for a ray of light
LiRa [457]

Answer:

\theta_i = 23^o

Explanation:

The refractive index of a medium is given by the following formula:

\eta = \frac{Sin\theta_i}{Sin\theta_r}

where,

η = refractive index = 1.5

\theta_i = angle of incidence = ?

\theta_r = angle of refraction = 15°

Therefore,

1.5 = \frac{Sin\theta_i}{Sin15^o}\\\\Sin\theta_i=(1.5)Sin15^o\\\\\theta_i = Sin^{-1}(0.388)\\\\

\theta_i = 23^o

4 0
3 years ago
Which statement is true about the scientific method?
dsp73

Answer: A. It follows one prescribed sequence of steps.

Explanation:

A scientific method can be define as the procedure which is required to be followed so as to prove the cause of a scientific phenomena. The scientific method usually consist of steps of experimentation procedures which are performed under controlled conditions so as to avoid any error in the observation as well as in the results. The scientific method is necessary to relate the experimental conditions with the nature.

3 0
4 years ago
The resistance of an electric heater is 50 Ω when connected to 120 V. How much energy does it use during 15 min of operation?
STALIN [3.7K]

Answer:

Explanation:

I = V/R = 120 V/ 50 Ω = 2.4 A

P = VI = 120(2.4) = 288 W = 288 J/s

288 J/s (15 min(60s / min)) = 259,200 J

or the electric company would charge for

288 W / (1000 W/kW)•(15/60) hr = 0.072 kW•hr

At $0.20 / kW•hr, that would be under 1½ cents

7 0
3 years ago
(a) Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t)
dolphi86 [110]

Answer:

r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k

Explanation:

a(t)=20t i+sin(t) j +cos(2t) k

v(t)=\int\limits^a_b {a(t)} \, dt

=(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k---------------eqn 1

given v(0)=i

i=c_1i+(-1+c_2)j+(0+c_3)k

c_1=1   c_2=1  c_3=0

from equation 1

V(t)=(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k----------eqn 2

now r(t)=\int\limits^a_b {v (t)} \, dt

(\frac{10t^3}{3}+t+c_1)i+(-sint+t+c_2)j+(\frac{-cos2t}{4}+c_3)k

given r(0)=j

0i+1j+ok = c_1i+c_2j+(\frac{-1}{4}+c_3)k

c_1=0  c_2=0  c_3 =  \frac{1}{4}

r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k

8 0
3 years ago
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