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2 years ago

What is the proper to do 81x400

Mathematics

2 answers:

ludmilkaskok [199]2 years ago

6 0

Answer:

Step-by-step explanation:

To perform this multiplication I would rewrite the expression as

81*4*100. This is easier to do mentally: 4 times 81 is 324, and then 324 times 100 is 32,400. There are of course other approaches involving factoring the original expression and performing multiplication.

Cerrena [4.2K]2 years ago

5 0

Answer:

81 x400

=32400

Step-by-step explanation:

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PLEASE ANSWER QUICKLY! WILL GIVE BRANLIEST

uysha [10]

Answer:

Step-by-step explanation:

Let x represent the seating capacity

Number of seats = 40+x

Profit per seat = 10 - 0.20x

For maximum number of seats

P(x) = ( 40+x ) ( 10-0.20x )

P(x) = 400+10x-8x-0.2x^2

P(x) = 400+2x- 0.2x^2

Differentiating with respect to ( x )

= 2 - 0.4x

0.4x = 2

x = 2/0.4

x = 5

The seating capacity will be 40+5 = 45

For the maximum profits

40X10+ 9.9 + 9.8 + 9.7 + 9.6 + 9.5 + 9.4 + 9.3 + 9.2 + 9.1 + ... 1.0, 0.9, 0.8, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1

= 400 + an arithmetic series (first term = 0.1, common difference = 0.1, number of terms = 8+ 40 = 48 )

= 400 + (48/2)(2X0.1 + (48-1)X0.1)

= 400 + 24(0.2 + 4.7)

= 400 + 24(4.9)

= 400 + 117.6

= 517.6

= 517.6dollars

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3 years ago

What's the average of 3.29,2.59,4.29 and 2.50 $

devlian [24]

The answer is $3.16

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Fill in the blank with the phrase that makes the proof statement true.

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4 years ago

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3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0

4 years ago