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zysi [14]
2 years ago
13

Find the distance and midpoint for the points (5,5) and (1,2).

Mathematics
1 answer:
stealth61 [152]2 years ago
5 0

Answer:

midpoint = (3,3.5)

distance = 5

Step-by-step explanation:

midpoint = (x1+X2/2, y2+y2/2)

=(5+1/2, 5+2/2)

=(6/2, 7/2)

=(3, 3.5)

distance= √(x2-x1)^2 -(y2-y1)^2

=√(1-5)^2 -(2-5)^2

= √ 16+9 =√25 =5

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Quadrilateral PUMA has coordinates at P(-5,-2), U(-1,2), M(4,-3), A(0,-7) and it is transformed by (x+3,y-5). Determined the ima
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The image of M is (7 , -8)

Step-by-step explanation:

Let us revise some transformation

  • If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)
  • If the point (x , y) translated vertically up by k units  then its image is (x , y + k)
  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

∵ The quadrilateral PUMA has coordinates at:

   P (-5 , -2) , U (-1 , 2) , M (4 , -3) , A (0 , -7)

∵ It is transformed by (x + 3 , y - 5)

- That means the quadrilateral translated 3 units right and 5 units

   down, then we add each x-coordinate by 3 and subtract 5 from

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∵ The coordinates of point M are (4 , -3)

∴ The image of point M = (4 + 3 , -3 - 5)

∴ The image of point M = (7 , -8)

The image of M is (7 , -8)

Learn more:

You can learn more about transformation in brainly.com/question/5563823

brainly.com/question/11203617

*LearnwithBrainly

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