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3 years ago

Write the equation of the line that passes through the points (9, -1) and (-6, -3).

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

8 0

Y-9=2/15(x+1)

point slope form of a line is y - y1 = m * (x - x1)

m is slope

Mark brainliest please

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Solve the equation. 2/3 - 4x 7/2= -9x+ 5/6 step by step

Lostsunrise [7]

Answer: $\bold{x=\dfrac{11}{21}}$

Step-by-step explanation:

$\dfrac{2}{3}-\dfrac{4x+7}{2}=-9x+\dfrac{5}{6}\\\\(6)\dfrac{2}{3}-(6)\dfrac{4x+7}{2}=-9x(6)+(6)\dfrac{5}{6}\qquad \text{(multiplied by LCD) }\\\\4 - 12x-21=-54x+5\qquad \text{(simplified)}\\\\-12x - 17 = -54x + 5\qquad \text{(added like terms)}\\\\42x-17=5\qquad \text{(added 54x to both sides)}\\\\42x = 22\qquad \text{(added 17 to both sides)}\\\\x=\dfrac{22}{42}\qquad \text{(divided both sides by 42)}\\\\x=\dfrac{11}{21}\qquad \text{(reduced the fraction)}$

NOTE: The sign between 4x and 7 is missing in the question you posted. I assumed it was 4x + 7 in order to solve the equation.

6 0

3 years ago

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Which of the following is equal to the rational expression when x doesnt equal 5? x^2 - 25/ x - 5

scoundrel [369]

The complete question in the attached figure

we have that
(x² - 25)/ (x - 5)

we know
(x² - 25)-------------> (Difference of two squares)----------> (x+5)*(x-5)

then

(x² - 25)/ (x - 5)-------> (x+5)*(x-5)/(x-5)------------> (x+5)

the answer is the option B)
(x+5)

4 0

3 years ago

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What is the answer to this question ?

romanna [79]

Just use a calculator and you will get -1/2

3 0

3 years ago

The decimal part of the number 62 .85 is a 62 b 0.8 c 0.85 d 85

Zigmanuir [339]

Answer:

1.7

Step-by-step explanation:

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3 years ago

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Start with the geometric power series LaTeX: 1+x+x^2+x^3+x^4+\cdots Substitute LaTeX: -x^3in place of LaTeX: x, and then take a

valina [46]

Answer:

$-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}$

Step-by-step explanation:

Given : $1+x+x^2+x^3+x^4+\cdots$

On putting $-x^3$ in place of x , we get $1+\left ( -x^3 \right )+\left ( -x^3 \right )^2+\left ( -x^3 \right )^3+\left ( -x^3 \right )^4+...$

On simplifying , we get $1-x^3+x^6-x^9+x^{12}+...$

On differentiating , we get $\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...$

Here ,

$-3x^2=\left ( -1 \right )^1\,3(1)x^{3(1)-1}\\6x^5=\left ( -1 \right )^2\,\,3(2)\,\,x^{3(2)-1}\\-9x^8=\left ( -1 \right )^3\,\,3(3)\,\,x^{3(3)-1}\\12x^{11}=\left ( -1 \right )^4\,\,3(4)\,\,x^{3(4)-1}$

Now , we need to express it using summation notation.

$\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}$

4 0

3 years ago