3 years ago

(cos2a cos 4a+ sin 2asin 4a)/sin4a

Mathematics

1 answer:

lyudmila [28]3 years ago

4 0

Answer:

Step-by-step explanation:

(cos 4a*cos 2a+sin 4a*sin 2a)/sin 4a

=[cos (4a-2a)]/sin 4a

=(cos 2a)/sin 4a

=(cos 2a) /(2 sin 2a cos 2a)

=1/(2 sin 2a)

=1/2 csc 2a

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(cos2a *cos 4a+ sin 2a*sin 4a)/sin4a

(cos2a cos 4a+ sin 2asin 4a)/sin4a