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Marysya12 [62]
3 years ago
5

Plz help me! Explain the solution

Mathematics
1 answer:
slavikrds [6]3 years ago
4 0

Answer:

C) ½

Step-by-step explanation:

In the given inequality statement: 2/5 < x < ¾

It means that, "<em>x</em> is less than ¾ and greater than 2/5."

Find out what the equivalent decimal values of each expression.

2/5 < x < ¾:

2/5 = 0.40

¾ = 0.75

Therefore, the value of x must be between 0.40 and 0.75.

A: 3/10  = 0.30 (not a solution for x).

B: 1/3 = 0.33 (not a value for x).

C: 1/2 = 0.50 (possible value for x)

D) 4/5 = 0.80 (not a value for x).

E) 5/6 = 0.83 (not a value for x).

As you can see, the only viable solution for x is ½, as it provides a true inequality statement: 2/5 < ½ < ¾

Therefore, the correct answer is C: ½

Please mark my answers as the Brainliest, if you find this helpful :)

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Answer:

QR = 1.3

Step-by-step explanation:

Sides TQ and TS are congruent, thus Δ QST is isosceles.

RT is a perpendicular bisector, that is it bisects QS at right angles, thus

QR = RS = 1.3

3 0
3 years ago
I will do brainiest! Show work!! plz help
rosijanka [135]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Solve this please asap !
Pavlova-9 [17]

Answer:

b = 120°

Step-by-step explanation:

The angle on the circle is half the central angle , that is

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7 0
3 years ago
Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the origin and (−3, 4).
oee [108]

Answer:

x = \frac{17}{18}

y = \frac{23}{6}

Step-by-step explanation:

Given

y = 3x + 1

Points = (0,0)\ to\ (-3,4)

Required

Determine (x,y) equidistant from the equation and the given point

This question will be answered using distance formula;

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

Considering The first Point (0,0)\ to\ (x,y)

(x_1 ,y_1) = (0,0)

(x_2,y_2) = (x,y)

The distance is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

d = \sqrt{0 - x)^2 + (0 - y)^2}

d = \sqrt{(- x)^2 + (- y)^2}

d = \sqrt{x^2 + y^2}

Considering the second point: (x,y)\ to\ (-3,4)

(x_1,y_1) = (x,y)

(x_2,y_2) = (-3,4)

The distance is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

d = \sqrt{(x - (-3))^2 + (y - 4)^2}

d = \sqrt{(x + 3)^2 + (y- 4)^2}

d = \sqrt{x^2 + 6x + 9 + y^2- 8y + 16}

d = \sqrt{x^2 + 6x + y^2- 8y + 16 + 9}

d = \sqrt{x^2 + 6x + y^2- 8y + 25}

Equate both values of d

\sqrt{x^2 + 6x + y^2- 8y + 25} =  \sqrt{x^2 + y^2}

Square both sides

x^2 + 6x + y^2- 8y + 25 = x^2 + y^2

Collect Like Terms

6x - 8y + 25 = x^2 -x^2+ y^2 -y^2

6x - 8y + 25 =0

Recall that y = 3x + 1

6x - 8(3x + 1) + 25 = 0

6x - 24x - 8 + 25 = 0

-18x+ 17 = 0

-18x=- 17

Solve for x

x = \frac{-17}{-18}

x = \frac{17}{18}

Substitute \frac{17}{18} for x in y = 3x + 1

y = 3 * \frac{17}{18} + 1

y = \frac{17}{6} + 1

y = \frac{17 + 6}{6}

y = \frac{23}{6}

8 0
3 years ago
Given the following formula solve for r
Crank

Answer:

D

Step-by-step explanation:

C = 2pir

<em>Divide both sides by 2pi</em>

C/(2pi) = 2pi/2pi r -->

C/(2pi) = r

That's D

5 0
3 years ago
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